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worty [1.4K]
3 years ago
6

How do you solve 5 + x2 = 2x2 + 13

Mathematics
1 answer:
dsp733 years ago
7 0
I honestly suggest downloading photomath, its like a calculator but you take a pic of the equation and it shows you how to do it
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Write the explicit rule for the arithmetic sequence
blagie [28]
Given that:
a1=27, an=(an-1)+4
the second term will be:
a2=a1+4
a2=27+4=31
The explicit formula for arithmetic sequence is given by:
an=a+(n-1)d
where:
a= first term
d=common difference
n=nth term
from the information given:
a=27
d=31-27=4
thus the explicit formula will be:
an=27+(n-1)4
an=27+4n-4
an=23+4n

Answer: an=23+4n
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2 years ago
Help guys plzzz asapppp
nignag [31]

sin(x) = opp/hyp
cos(x) = adj/hyp
tan(x) = opp/adj

sin(x) = 3.9/8.1
sin(x) = 0.481

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Each answer should be between 0 and 90 :)
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2 years ago
doug entered a canoe race. he rowed 3 1/2 miles in 1/2 hour. what is his average speed in miles per hour?
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Average speed = total distance / total time...

s=3.5/0.5=7mph
6 0
3 years ago
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Which of the following is the correct graph of the compound inequality 4p + 1 > −7 or 6p + 3 < 33?. . A.a number line with
r-ruslan [8.4K]

We are given compound inequality 4p + 1 > −7 or 6p + 3 < 33.

Let us solve each of the inequality one by one.

4p + 1 > −7

Subtracting 1 from both sides, we get

4p + 1-1 > -7-1

4p > -8

Dividing both sides by 4, we get

p > -2.    <em>  (Shading right side for greater than sign)</em>

Solving 6p + 3 < 33.

Subtracting 3 from both sides, we get

6p + 3-3 < 33-3.

6p < 30

Dividing both sides by 6, we get

p < 5. <em> (Shading left for less than sign)</em>

<em>We have less than and greater than symbols in both inequalities, therefore we would have open circles(dots) on -2 and 5.</em>

And because we have "OR" composite inequality.

<em>So, we would take the combination of both shaded portion.</em>

<h3>Therefore, correct option is C.number line with shading everywhere.. </h3>
4 0
3 years ago
What is the x-value of the solution? -x + 2y = 6 6y= x + 18
oksano4ka [1.4K]
Our x equals 0 so the answer is 0

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2 years ago
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