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4 years ago

9

Harvard University accepts 6 students for every 100 applicants. How many students will be accepted in 850 applicants apply for a

dmission?

1 answer:

balandron [24]4 years ago

4 0

60 Students will be accepted.

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1.3. If Sara draws a red ball and DOES NOT RETURN it, and then she goes to draw a green

dimulka [17.4K]

Answer:

Dependent Event

Step-by-step explanation:

Assume that are 10 balls, such that:

$Red = 6$

$Green = 4$

If the balls are replaced after taken, the probability is:

$Pr(Red) = 6/10$

$Pr(Green) = 4/10$

This is referred to as independent event; because each selection do not affect the next or previous selection

However, if the balls are not replaced, the probability is:

$Pr(Red) = 6/10$

$Pr(Green) = 5/(10 - 1) = 5/9$

We subtracted 1 because there is a reduction in the number of balls when the red ball is not returned.

This is referred to as independent event; because a selection affects the next selection

3 0

3 years ago

There are 30 seventh-grade students and

Alisiya [41]

The answer is A. 1 to 3

8 0

3 years ago

Identify the Minimum, First Quartile, Median, Third Quartile, and Maximum for the data.

Ymorist [56]

Answer:

I think we are missing data, so this is impossible to answer.

3 0

3 years ago

What is the slope of the line of (18, 28 ) (6,8)?

Finger [1]

Answer:

5/3

Step-by-step explanation:

to find the slope, we have to use the formula y2-y1 over x2-x1. Now, plug in our values; 8-28 over 6-18. Our answer becomes -20 over -12 this simplifies to 5 over 3, and there's your answer.

4 0

3 years ago

Doug hits a baseball straight towards a 15 ft high fence that is 400 ft from home plate. The ball is hit 2.5ft above the ground

Scorpion4ik [409]

Answer:

$125.4\ \text{m/s}$

Step-by-step explanation:

u = Initial velocity of baseball

$\theta$ = Angle of hit = $30^{\circ}$

x = Displacement in x direction = 400 ft

y = Displacement in y direction = 15 ft

$y_0$ = Height of hit = 2.5 ft

$a_y$ = g = Acceleration due to gravity = $32.2\ \text{ft/s}^2$

t = Time taken

Displacement in x direction

$x=u_xt\\\Rightarrow x=u\cos\theta t\\\Rightarrow t=\dfrac{x}{u\cos\theta}\\\Rightarrow t=\dfrac{400}{u\cos30^{\circ}}\\\Rightarrow t=\dfrac{400}{u\dfrac{\sqrt{3}}{2}}\\\Rightarrow t=\dfrac{800}{u\sqrt{3}}$

Displacement in y direction

$y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow y=y_0+u\sin\theta t+\dfrac{1}{2}a_yt^2\\\Rightarrow 15=2.5+u\sin30^{\circ}(\dfrac{800}{u\sqrt{3}})+\dfrac{1}{2}\times -32.2\times (\dfrac{800}{u\sqrt{3}})^2\\\Rightarrow \dfrac{400}{\sqrt{3}}-\dfrac{10304000}{3u^2}-12.5=0\\\Rightarrow 218.44=\dfrac{10304000}{3u^2}\\\Rightarrow u=\sqrt{\dfrac{10304000}{3\times218.44}}\\\Rightarrow u=125.4\ \text{m/s}$

The minimum initial velocity needed for the ball to clear the fence is $125.4\ \text{m/s}$

5 0

3 years ago