Answer:
We accept H₀ , we do not have enought evidence for rejecting H₀
Step-by-step explanation:
Normal Distribution
sample size n = 60
standard deviation σ = 15
1.Hypothesis Test : Is a one tailed-test on the right
H₀ null hypothesis μ₀ = 50
Hₐ alternative hypothesis μ₀ > 50
2.-We will do the test for a significance level α = 0,01 tht means for a 99% interval of confidence
then z(c) = 2.32
3.- We compute z(s)
z(s) = [ ( μ - μ₀ ) /( σ/√n ) ⇒ z(s) = ( 2 * √60 ) / 15
z(s) = 15.49/15 ⇒ z(s) = 1.033
4.- We compare values of z(c) and z(s)
z(s) < z(c) 1.033 < 2.32
z(s) is in the acceptance region so we accept H₀ , we do not have enough evidence for rejecting H₀
The ratio of the areas is 340/1158 = 170/579thus the ratio of the side lengths is sqrt(170)/sqrt(579) = .5418the ratio of volumes is the side length ratio cubed = .5418^3 = .159Volume of smaller solid = (.159)(1712) = 272.37
Answer:
V≈421.88
Step-by-step explanation:
You would do 120/300 = p/100 and you would get 40%
