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Rama09 [41]
2 years ago
15

Solve for u. m/u^2+r=−k−y

Mathematics
1 answer:
mylen [45]2 years ago
7 0

9514 1404 393

Answer:

  u = ±√(-m/(k+r+y))

Step-by-step explanation:

Subtract r, rearrange, then take the square root.

  \dfrac{m}{u^2}+r=-k-y \qquad\text{given}\\\\ \dfrac{m}{u^2}=-k-y-r\\\\-\dfrac{m}{k+r+y}=u^2\\\\ \boxed{u=\pm\sqrt{-\dfrac{m}{k+r+y}}}

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A dog jumps straight up. Y=-16t^2+20t models the motion of the dog, where "t" is the time in seconds and "y" is the height of th
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Answer:

Step-by-step explanation:

The motion of the dolphin is quadratic

i.e y=-16t²+20t

To get the maximum height the dolphin will reach

We need to find the point of inflexion. i.e dy/dt=0

dy/dt=-32t+20

Then set dy/dt=0

0=-32t+20

Then, -32t=-20

t=0.625

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d²y/dt²=-32. Since this is negative then the point t=0.625 is the maximum point the dolphin can reach

Then substitute t=0.625 into y

y=-16t²+20t

y=-16(0.625)²+20(0.625)

y=6.25ft

Then the maximum height the dolphin can reach is 6.25ft

Using discriminant

Formular method

y=-16t²+20t

So the dog height y<7

y=-16t²+20t <7

-16t²+20t-7<0

a=-16, b= 20. c=-7

t=(-b±√b²-4ac)/2a

Using the a, b and c direct for the discriminant

D=b²-4ac

D=20²-4×-16×-7

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Which is a complex number

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Then we need to model the D to be greater than 0

Therefore,

D>0

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We cannot do anything to a and b it is already given

a=-16, b=20

(20)²-4(-16c)>0

400+64c>0

64c>-400

Then

c>-6.25

Divide both side by - and the inequality sign will change

Therefore -c<6.25

So the dog height y<6.25

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Therefore the maximum height is 6.25.

If it is greater than that then, we are going to have a complex root movement which is not possible for the dolphin .

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3 years ago
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To find a volume of a cylinder we use the following formula:
v = \pi {r}^{2} h
Plug in the values:

v = \pi \times  {8}^{2}  \times 14
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v = \pi \times 64 \times 14
Multiply the numbers:
v =896 \pi {m}^{2}
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The Robinson family traveled a total of 240 miles in 6 hours on their trip to visit relatives. If they travel at a constant, pro
ivanzaharov [21]

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Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

Null hypothesis: ∪ =  No possible child abuse or neglect

Alternative hypothesis: Uₐ = Possible child abuse or neglect

A type I error occurs when you reject the null hypothesis when it is true. In this situation, a type I error occurs when you conclude on possible child neglect or abuse and place the child in protective custody

A type II error occurs when you accept the null hypothesis when it is false. In this instance, a type II error occurs when you conclude on no possible child abuse or neglect when there is and fail to remove the child from the home.

In this case, the type II error is the more serious error. Failure to remove the child when there is possible child abuse or neglect will lead to more detrimental effect. Although, the type I error is also serious, it is not so detrimental as the type II error.

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