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Zinaida [17]
2 years ago
9

What is the GCF for each set of numbers 15 and 35. show ur work

Mathematics
2 answers:
In-s [12.5K]2 years ago
8 0
15
3 x 5 or 5 x 3
35
5 x 7 or 7 x 5
So the answer is 5
Helga [31]2 years ago
8 0
GCF= 5
Factors of 15: 1,3,5,15, Factors of 35: 1,5,7,35
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Select the linear equation represented in the graph.
AleksAgata [21]

Answer:

y = \frac{1}{2} x + 3

Step-by-step explanation:

use y = mx + b

slope(m) = \frac{1}{2}

y-intercept(b) = 3

so,

y = \frac{1}{2} x + 3

6 0
3 years ago
Find dy/dx by implicit differentiation. y cos x = 5x2 + 3y2
lbvjy [14]
Step 1:
Start by putting \frac{d}{dx} in front of each term

\frac{d}{dx}[y cos x]= \frac{d}{dx}[5x^2]+ \frac{d}{dx}[ 3y^2]
-----------------------------------------------------------------------------------------------------------------
Step 2:

Deal with the terms in 'x' and the constant terms
\frac{d}{dx}[ycosx]= 10x+ \frac{d}{dx} [3y^2]
----------------------------------------------------------------------------------------------------------------
Step 3:

Use the chain rule for the terms in 'y'
\frac{d}{dx}[ycosx]=10x+6y \frac{dy}{dx}
--------------------------------------------------------------------------------------------------------------
Step 4:

Use the product rule on the term in 'x' and 'y'
(y) \frac{d}{dx} cos x+(cos x) \frac{d}{dx}y =10x+6y \frac{dy}{dx}

y(-siny)+(cosx) \frac{dy}{dx} =10x+6y \frac{dy}{dx}
--------------------------------------------------------------------------------------------------------------

Step 5:

Rearrange to make \frac{dy}{dx} the subject
-y sin(y)+cos(x) \frac{dy}{dx} =10x+6y \frac{dy}{dx}
cos(x)  \frac{dy}{dx}-6y \frac{dy}{dx}=10x+y sin(y)
[cos(x) - 6y]  \frac{dy}{dx}=10x + y sin(y)
\frac{dy}{dx}= \frac{10x+ysin(y)}{cos(x)-6y} ⇒ Final Answer


5 0
3 years ago
What is the conjugate? √x + 2√b
Llana [10]
The correct answer is:  " √x  −  <span>2√b " .
</span>_________________________________________________________

       The "conjugate" of  " √x  + 2√b "  is:  " √x  −  2√b " .
_________________________________________________________

Explanation:
_________________________________________________________
      In an expression with 2 (TWO) terms;  that is, in a "binomial expression", 
the "conjugate" of that expression refers to that very expression — with the "sign" in between those two terms—"reverse" (e.g. "minus" becomes "plus" ; or, "plus" becomes "minus" .) .
_________________________________________________________ 

      →  So:  We are given:  " <span>√x + 2√b " .
</span>
      →  Note that this is a "binomial expression" ;

      →  that is, there are 2 (TWO) terms:  " <span>√x " ; and:  " 2√b " .
_________________________________________________________

To find the "conjugate" of the given binomial expression:

     </span>→  " <span>√x + 2√b "  ; 

     </span>→  We simply change the "+" {plus sign} to a "<span>−"  {minus sign} ;  and rewrite:
___________________________________________________________

     </span>→  " √x − 2√b "  ; 

     →  which is the "conjugate" ; and is the correct answer:
___________________________________________________________
→  " √x − 2√b " ;   is the "conjugate" of the expression:  " <span>√x + 2√b " . 
___________________________________________________________
     
</span>→  {that is:  " √x − 2√b " ;  is the conjugate.}.
___________________________________________________________
7 0
3 years ago
You lose one quarter, two dimes, and two nickels.
torisob [31]

are you sure this is full question?

7 0
3 years ago
Read 2 more answers
hi friends..please help me..it's very urgent... please give the solutions of the given bits... please....​
Komok [63]
Hey I don’t know much of this but I really recommend you to re ask this question but choose the other option to talk to an expert :)
3 0
3 years ago
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