Answer:

Step-by-step explanation:
We have been given a function
. We are asked to find the zeros of our given function.
To find the zeros of our given function, we will equate our given function by 0 as shown below:

Now, we will factor our equation. We can see that all terms of our equation a common factor that is
.
Upon factoring out
, we will get:

Now, we will split the middle term of our equation into parts, whose sum is
and whose product is
. We know such two numbers are
.




Now, we will use zero product property to find the zeros of our given function.




Therefore, the zeros of our given function are
.
Assume P(xp,yp), A(xa,ya), etc.
We know that rotation rule of 90<span>° clockwise about the origin is
R_-90(x,y) -> (y,-x)
For example, rotating A about the origin 90</span><span>° clockwise is
(xa,ya) -> (ya, -xa)
or for a point at H(5,2), after rotation, H'(2,-5), etc.
To rotate about P, we need to translate the point to the origin, rotate, then translate back. The rule for translation is
T_(dx,dy) (x,y) -> (x+dx, y+dy)
So with the translation set at the coordinates of P, and combining the rotation with the translations, the complete rule is:
T_(xp,yp) R_(-90) T_(-xp,-yp) (x,y)
-> </span>T_(xp,yp) R_(-90) (x-xp, y-yp)
-> T_(xp,yp) (y-yp, -(x-xp))
-> (y-yp+xp, -x+xp+yp)
Example: rotate point A(7,3) about point P(4,2)
=> x=7, y=3, xp=4, yp=2
=> A'(3-2+4, -7+4+2) => A'(5,-1)
Answer:
It would be y = 40x
The new equation is y = 45x
Step-by-step explanation:
I did the other question you put ;)
Answer:
5
Step-by-step explanation:
substitute 2 for t
-16(2)^2+32(2)+5=5
Answer:
sorry but imma destroy ya
Step-by-step explanation: