X/3 -4 = -29 what does X equal? Plz help

Question 5<br> Solve for n.<br> HELP ASAP ILL GIVE U BRAINEST

11111nata11111 [884]

Answer:

The correct answer is – 4/7

7 0

3 years ago

Read 2 more answers

A certain fraction is greater than 2. The denominator is 8. What must be true about the numerator?

Volgvan

Answer:

The numerator must be greater than 16

Step-by-step explanation:

We are told that a certain fraction is greater than 2. Thus, if the numerator and denominator are x and y respectively, then we have;

x/y > 2

We are further told that the denominator is 8.

Thus;

x/8 > 2

Multiply both sides by 8 to give;

x > 16

Thus,the numerator must be greater than 16.

5 0

3 years ago

A shopper paid $2.52 for 4.5 pounds of potatoes,$7.75 for 2.5 pounds of broccoli,and $2.45 for 2.5 pounds of pears.What is the u

Sidana [21]

Answer:

Step-by-step explanation:

A shopper paid $2.52 for 4.5 pounds of potatoes. This means that the unit price for each potato would be

2.52/4.5 = 0.55556

Approximately $0.6 per pound.

The shopper paid $7.75 for 2.5 pounds of broccoli. This means that the unit price for each broccoli would be

7.75/2.5 = $3.1 per pound.

The shopper paid $2.45 for 2.5 pounds of pears. This means that the unit price for each pear would be

2.45/2.5 = $0.98 per pound

6 0

3 years ago

PLEASE a help me (pre algebra)

irakobra [83]

Answer:

it's in order

1. j: 71

2. j: 16

3. j: 10

4. j: 68

5. j: 61

4 0

3 years ago

Read 2 more answers

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want to find $P(X \geq 1)$

So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067$

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is made

c) What is the probability that seven people make a purchase in the next four minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

$\mu = 4*5 = 20$

We have to find P(X = 7).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005$

0.05% probability that seven people make a purchase in the next four minutes

8 0

3 years ago