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9966 [12]
3 years ago
7

You select a card at random from the cards that make up the word “replacement”. Without replacing the card, you choose a second

card. Find the probability of choosing a consonant and then an “e”. There is 1 letter for each card.
Mathematics
1 answer:
natta225 [31]3 years ago
6 0
To find the total probability, we first need to solve for the probability of the individual events.

Event 1:
P(consonant)=7/11
We know this to be true because out of the 11 total possibilities for the event, 7 of them are consonants.
R E P L A C E M E N T 


Event 2
P(e)=3/10
We know this to be true because out of the 10 total possibilities for the event (since we didn't replace the first card we withdrew), 3 of them are the letter 'e'.
R E P L A C E M E N T (-1 to account for the first card we withdrew)

The possibility of both events...

P(consonant then 'e')=7/11*3/10=21/110

Answer: P=21/110
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DochEvi [55]

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\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

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Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

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