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9966 [12]
3 years ago
7

You select a card at random from the cards that make up the word “replacement”. Without replacing the card, you choose a second

card. Find the probability of choosing a consonant and then an “e”. There is 1 letter for each card.
Mathematics
1 answer:
natta225 [31]3 years ago
6 0
To find the total probability, we first need to solve for the probability of the individual events.

Event 1:
P(consonant)=7/11
We know this to be true because out of the 11 total possibilities for the event, 7 of them are consonants.
R E P L A C E M E N T 


Event 2
P(e)=3/10
We know this to be true because out of the 10 total possibilities for the event (since we didn't replace the first card we withdrew), 3 of them are the letter 'e'.
R E P L A C E M E N T (-1 to account for the first card we withdrew)

The possibility of both events...

P(consonant then 'e')=7/11*3/10=21/110

Answer: P=21/110
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3 years ago
(a) A mixed hockey team of 11 must have at least 5 boys and at least 5 girls. There are 7 boys and 8 girls available for selecti
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Answer:

A) I) 49 teams

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B) 28 teams

Step-by-step explanation:

A) a team of 5 boys and 6 Girls

=7C5+ 8C6

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a team of 6 boys and 5 girls

= 7C6 + 8C5

= 7+56

= 63 teams

B) one girl is kept constant already and a guy has injury

Girls remaining to choose from 7

Boys remaining to choose from 6

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= 28 teams

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2 years ago
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patriot [66]

There are two different ways you can do this, I have provided both below.

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Answer: Flip the graph over the line of y = x

   I have attached an example from<em> lumenlearning.com</em>.

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M.<br> 4.96)2,9.76<br> Need Answer to how much does 4.96 go into 2976
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Answer:600

Step-by-step explanation:2,976/4.96=600

3 0
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Pretty PLEASE can you help me solve this? I know that the answer is not (-5, -3), if that helps.
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<em>Please refer to the attachment for the answer and explanation. Hope it helps!!</em>

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