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2 years ago

Area of paralellogram with base 15cm and height12cm

Mathematics

2 answers:

azamat2 years ago

7 0

Answer:

180 cm2

Area of a polyhedron:

15(=base)x12(=height)

=180cm2

btw parallelogram is a 2D pic how you can come out a ''base'' and ''height''? It should be called a polyhedron. Your question is weird.

If so, your ''area of parallelogram'' is 15cm2 since your question is hecking weird.

Btw it's 15cm2 not 15

Please check ur question b4 u ask

Alenkasestr [34]2 years ago

3 0

180 square cm. The formula for the area of a parallelogram is base x height. Base and height as in the figure below:

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liubo4ka [24]

Answer:

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Step-by-step explanation:

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3 years ago

Find the values of the variables for the parallelogram if m<1=4y-2. Round your answers to two decimal places if necessary!

hichkok12 [17]

The prallelogram whose adjacent sides are equal and one vertex angle is 90 degrees is a square.

The value of angle 1 is 90 degrees as the diagonal of the square intersect at 90 degrees.

$\begin{gathered} 4y-2=90 \\ 4y=92 \\ y=23 \end{gathered}$

The value of y is 23.

The diagonal of the square bisect the vertex angle hence the angle of 3x is 45 degrees.

$\begin{gathered} 3x=45 \\ x=15 \end{gathered}$

Thus, the value of x is 15 degrees.

The value of 12z is 45 degrees.

$\begin{gathered} 12z=45 \\ z=3.75 \end{gathered}$

Thus, the required value of z is 3.75 degrees.

3 0

1 year ago

Vignesh owns a cottage in the shape of a cube with each edge of length 26 feet. The roof is in the shape of a square pyramid and

Zina [86]

Answer:

56√93 ≈ 540 ft²

Step-by-step explanation:

The roof is made up of 4 congruent isosceles triangles. Since the roof extends 2 ft over the edge of the cottage on each side, then the base of each triangle is 26 + 2 = 28 ft.

Let's calculate the area of one of the triangles and then just multiply by 4. See attachment. Drop a perpendicular from the vertex of a triangle to its base. We now have the triangle broken up into two right triangles. The hypotenuse is 17 ft and one of the legs of the right triangle is 28 / 2 = 14 ft. Then the height / other leg is:

$\sqrt{17^2-14^2} =\sqrt{289-196} =\sqrt{93}$

We now have the dimensions of each triangle: the height is √93 and the base is 28. The area of a triangle is: A = (1/2) * b * h, so we have the following.

A = (1/2) * b * h

A = (1/2) * 28 * √93 = 14√93

Multiply this by 4:

14√93 * 4 = 56√93

The total surface area is 56√93 ≈ 540 ft².