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3 years ago

13

PLEASE HELP IN ONE MINUTE WILL MARK BRAINLIST

1 answer:

evablogger [386]3 years ago

4 0

Answer:

y=-2/3x+3

Step-by-step explanation:

The y intercept is (0,3)

another point on the graph is (3,1)

You might be interested in

Do the ratios 2-4 and 14-7 form a proportion

Nadya [2.5K]

Answer:

No

Step-by-step explanation:

because 2 is divisible by 14 but 4 is not divisible by 17

3 0

3 years ago

Read 2 more answers

Which is bigger 7/8 or 13/16

salantis [7]

To compare these fractions, bring them to the same denominator. Expand the fractions to bring them to the common denominator (LCM):

7/8 = (2 * 7) / (2 * 8) = 14/16
13/16 = (1 * 13) / (1 * 16) = 13/16

Same denominator fractions sorted ascending:

13/16 < 14/16

Initial fractions in ascending order:

13/16 < 7/8

8 0

4 years ago

Read 2 more answers

PLEASE HELP I NEED HELP

Kisachek [45]

Answer:

5

Step-by-step explanation:

SQ= 10

SO is half way so divide by 2

8 0

3 years ago

please help me. how would you change x + 3y = 18 -3x -12y = -75 to eliminate y showing all of the work

Svetlanka [38]

Answer:

x = -3

y = 7

Step-by-step explanation:

x + 3y = 18

-3x - 12y = -75

multiply first equation by 4

4 × (x + 3y) = 18 ➡ 4x + 12y = 72

now add the two equations up

4x + 12y - 3x -12y = 72 - 75 (-12y will eliminate 12y)

x = -3

5 0

3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

laiz [17]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

8 0

3 years ago