<h2>Answer:</h2>
8.75 feet
<h2>
Step by step:</h2>
Given that a 12 foot ladder leans against a building seven feet above the ground.
By using trigonometry ratio, the angle between the ladder and the ground will be
SinØ = opposite/ hypothenus
SinØ = 7 / 12
SinØ = 0.58333
Ø = Sin^-1(0.58333)
Ø = 35.69 degree
At what height would an 15 foot ladder touch the building if both ladders form the same angle with the ground?
Using the same trigonometric ratios
SinØ = opposite/hypothenus
Sin 35.69 = opposite/ 15
Cross multiply
Opposite = 15 × sin 35.69
Opposite = 8.75 feet
Therefore, the ladder will touch the building if both ladders form the same angle with the ground at height 8.75 feet.
Twenty one and negative twenty one
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
SIDE OF THE SQUARE = 6 cm = DIAMETER OF THE CIRCLE.
AREA OF THE CIRCLE = (Pi/4)*6^2 = [(22/7)/4]*36 = 22*9/7 = 28.2857 sqcm
or
First, find the side length of the square. (Find the square root of 36 cm^2, to get 6 cm as the side length of the square).
Second, find the radius of the circle inside the square. The side length of the square is the diameter of the circle. Radius is half of the diameter. So, half of 6 cm is 3 cm; this is the radius of the circle.
Third, find the area of the circle by using the formula, A = pi x radius x radius
so, Area = 3.14 x 3 cm x 3 cm
by calculation we get the area of the circle is 28.26 cm^2
Where pi is a constant of 22/7 or 3.14
