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dlinn [17]
3 years ago
12

From two cities that are 500 mi apart, two cars left simulaneously moving towards each other. The speed of one car was 10 mph gr

eater than the speed of the other car. In 5 hours the cars met. Find the speed of each car.
Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0

Given:

Distance between to cities = 500 mi

Two cars left simultaneously moving towards each other.

The speed of one car was 10 mph greater than the speed of the other car.

They meet in 5 hours.

To find:

The speed of each car.

Solution:

Let x mi/h be the speed of one car.

So, speed of second car = (x + 10) mi/h

Two cars left simultaneously moving towards each other.

So, their relative speed = x + (x+10) = (2x+10) mi/h

We know that,

Speed =\dfrac{Distance}{Time}

On substituting the values, we get

2x+10=\dfrac{500}{5}

2x+10=100

2x=100-10

2x=90

Divide both sides by 2.

x=\dfrac{90}{2}

x=45

Now,

Speed of one car = 45 mi/h

Speed of other car = 45+10

                                = 55 mi/h

Therefore, the speeds of two cars are 45 mi/h and 55 mi/hr.

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marin [14]

Answer:

a) \sigma_{\bar X}= \frac{1.26}{\sqrt{165}}= 0.0981

b) We expect 68% of the values between : (6.6219, 6.8181)

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the total sleep time of a population, and for this case we know the distribution for X is given by:

X \sim N(6.72,1.26)  

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For this case the sample mean have the following distirbution

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

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\sigma_{\bar X}= \frac{1.26}{\sqrt{165}}= 0.0981

in minutes?= (Round your answer to three decimal places.)  

(b)  Use the 95 part of the 68–95–99.7 rule to describe the variability of this sample mean. (Round your answer to four decimal places.)

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

We expect 68% of the values between : (6.6219, 6.8181)

We expect 95% of the values between : (6.5238, 6.9162)

We expect 99.7% of the values between : (6.4257, 7.0143)

(c) What is the probability that your average will be below 6.9 hours? (Round your answer to four decimal places.)

For this case we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And we can find the z score for 6.9 and we got:

z = \frac{6.9-6.72}{0.0981}= 1.835

And we can use the z normal table or excel and we got:

P(Z

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Step-by-step explanation:

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