From two cities that are 500 mi apart, two cars left simulaneously moving towards each other. The speed of one car was 10 mph gr
1 answer:
Given:
Distance between to cities = 500 mi
Two cars left simultaneously moving towards each other.
The speed of one car was 10 mph greater than the speed of the other car.
They meet in 5 hours.
To find:
The speed of each car.
Solution:
Let x mi/h be the speed of one car.
So, speed of second car = (x + 10) mi/h
Two cars left simultaneously moving towards each other.
So, their relative speed = x + (x+10) = (2x+10) mi/h
We know that,
On substituting the values, we get
Divide both sides by 2.
Now,
Speed of one car = 45 mi/h
Speed of other car = 45+10
= 55 mi/h
Therefore, the speeds of two cars are 45 mi/h and 55 mi/hr.
You might be interested in
and
. So we have a remainder of
and
. Subtracting this from the previous remainder gives a new remainder
and
. Subtracting this from the previous remainder gives a new one of
and we're done since 2 does not divide . So we have