Answer:
3960.4 bacteria
Step-by-step explanation:
The formula to solve the above question is given as:
P(t) = Po (2) ^t/k
P(t) = Population after time t = ?
Po = Initial population = 650 bacteria
t = Time in days = 7.3 days
k = doubling time = 2.8 days
P(t) = 650 × (2)^7.3/2.8
P(t) = 650 × 2^2.6071428571
P(t) = 650 × 6.0929582599
P(t) = 3960.4228689 bacteria.
Approximately = 3960.4 bacteria
Therefore, the number of bacteria the researcher will have after 7.3 days if they started with 650 bacteria is 3960.4 bacteria.
Add 6 to both sides
Solution: k = -30
Hmmmm...... Are you a 6th grader? I remember doing these in 6th grade.
Answer:
the first number is 5 the second number is 4
Step-by-step explanation:
first number = x
second number = y
X+2y=13 given this isolate x x = 13-2y
2x+y=14 substitute 13-2y for x
2(13-2y)+y=14
26-4y+y=14
-3y=-12
y=4 taking this number substitute into either equation above
x+2(4)=13
x+8=13
x=5
