X^3-6x^2 11x-6=0 a. 1,-5,4 1/3 b. 1,5,4 1/3 c. 0,-5,-4 1/3 d. 0,5,-4 1/3
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Given:
Dimensions of a tank are 50 cm by 32 cm by 20 cm
The tank is full of water and sand
Ratio of volume of water to the volume of sand is 5:1
To find:
Volume of water in the tank in liters
Solution:
Without loss of generality, let,
Length of tank = 50 cm
Breadth of tank = 32 cm
Height of tank = 20 cm
Then, we have,
Total Volume of the tank = Length * Breadth * Height
Total Volume = 50*32*20 cc
Total Volume = 32000 cc
It is given that,
Volume of water : Volume of sand = 5:1
(Volume of water)/(Volume of sand) = 5/1
Cross multiplying, we have,
Volume of sand = (Volume of water)/5
It is also given that the tank is full of water and sand. This implies that,
Volume of water + Volume of sand = Total Volume
Using the value, we obtained, we get,
Volume of water + (Volume of water)/5 = Total Volume
(6 * Volume of water)/5 = Total Volume
Plugging in the value of total volume, we get,
(6 * Volume of water)/5 = 32000 cc
Volume of water =
cc
Volume of water
26,666.6667 cc
We know that,
1 cc = 0.001 liters
26,666.6667 cc = (26666.6667 * 0.001) liters
26,666.6667 cc
26.667 liters
Thus, Volume of water in the tank is approximately 26.667 liters
Final Answer:
Volume of water in the tank (in liters) is approximately 26.667 liters
Answer:
54°
Step-by-step explanation:
Your triangle is isosceles. You have been given the third angle, and you have been asked to find the measure of one of the two equal angles. We know that the internal angles of a triangle sum to 180, so