I can conclude that the sign of the other integer is positive and that the other integer is 6 or greater.
I tried explaining it, but failed miserably. I'm so sorry! :(
Answer:
C = 5Q
Step-by-step explanation:
C = Length of Cloth in Meters (C)
Q = Number of Quilts Made (Q)
C = 5Q
Change C for the numbers under (Length of Cloth in Meters (C))
Nad change Q for the numbers under (Number of Quilts Made (Q))
So the new equations would be:
0 = 5(0) ---------> 0 = 0
5 = 5(1) ---------> 5 = 5
10 = 5(2) ---------> 10 = 10
15 = 5(3) ---------> 15 = 15
20 = 5(4) ---------> 20 = 20
25 = 5(5) ---------> 25 = 25
So the only option that amkes sense is (C = 5Q)
Answer:
![\frac{35}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B35%7D%7B2%7D)
Step-by-step explanation:
To solve this problem we need to write the mixed fraction as a fractional number, as follows:
![3 1/3 = 3 + \frac{1}{3} = \frac{9+1}{3} = \frac{10}{3}](https://tex.z-dn.net/?f=3%201%2F3%20%3D%203%20%2B%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20%5Cfrac%7B9%2B1%7D%7B3%7D%20%3D%20%5Cfrac%7B10%7D%7B3%7D)
![5 1/4 = 5 + \frac{1}{4} = \frac{20+1}{4} = \frac{21}{4}](https://tex.z-dn.net/?f=5%201%2F4%20%3D%205%20%2B%20%5Cfrac%7B1%7D%7B4%7D%20%3D%20%5Cfrac%7B20%2B1%7D%7B4%7D%20%3D%20%5Cfrac%7B21%7D%7B4%7D)
Then, evaluating the expression:
×
= ![\frac{210}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B210%7D%7B12%7D)
→ ![\frac{35}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B35%7D%7B2%7D)
Smaller number=x
larger number=2x+4
x+2x+4=70
3x+4=70
3x=66
x=22
Smaller number=22
When you add integers, you keep the sign on the sum.
For example:
-9 + -9 = -18 (kept the sign)
9 + 9 = 18 (kept the "sign")