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3 years ago

Rotation / reflection question PICTURE INCLUDED

Mathematics

1 answer:

Viefleur [7K]3 years ago

7 0

Answer S seems the best way to show that its equal. Correct me if I’m wrong please.

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Mika placed $4200 in a savings account which compounds interest continuously at a rate of 2.3%. How much will she have in the ac

OleMash [197]

Mika placed $4200 in a savings account which compounds interest continuously at a rate of 2.3%.

How much will she have in the account after 3 years?

1st year 4200 x 1.023 = 4296.60

2nd year 4296.60 x 1.023 = 4395.4218

3rd year 4395.4218 x 1.023 = 4496.5165

Round to the nearest dollar.

$4497

6 0

3 years ago

Which is irrational? <br> 32/3<br> 1.7284927172646362.....<br> 1.3232323232....<br> 1.5

emmasim [6.3K]

Answer:

Step-by-step explanation:

32/3

=10.666666667

4 0

3 years ago

Help I’ll mark brainliest

Thepotemich [5.8K]

Answer:

The 2nd one.

Step-by-step explanation:

6 0

3 years ago

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

5 0

3 years ago

HELP HELP HELP PLSSS

FromTheMoon [43]

Answer:

option. c. 720°

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5 0

2 years ago

Read 2 more answers