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Neporo4naja [7]
3 years ago
9

How do you work out the range in a dot plot

Mathematics
1 answer:
son4ous [18]3 years ago
7 0

Answer:

By examining the line plot, we find the number with the maximum number of crosses or occurrences. This gives the mode of the data set. We find the smallest and the largest number from the data set and find their difference and this difference is the range of the given data set.

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Which one of the following is an arithmetic senquence?
PtichkaEL [24]

Answer:

  D.  -2, 1, 4, 7, 10

Step-by-step explanation:

An arithmetic sequence has a common difference between terms. We can see if the offered choices have that characteristic:

  A. .5 -.35 = .15; .85 -.5 = .35 ≠ .15 . . . . not an arithmetic sequence

  B. 0 -5 = -5; -1 -0 = -1 ≠ -5 . . . . not an arithmetic sequence

  C. 3 -2 = 1; 5 -3 = 2 ≠ 1 . . . . not an arithmetic sequence

  D. 1 -(-2) = 3; 4 -1 = 3; 7 -4 = 3; 10 -7 = 3 . . . . common difference of 3, an arithmetic sequence

The appropriate choice is ...

  D.  -2, 1, 4, 7, 10, ...

8 0
3 years ago
Read 2 more answers
What is 5 2/3 + (-3 7/15)
Strike441 [17]

Answer:

i believe its 2.2

Step-by-step explanation:

7 0
3 years ago
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Evaluate 2 tan 45 - tan 60​
Darya [45]

Answer:

2 - √3

Step-by-step explanation:

tan45 = 1

tan60 = √3

2 tan 45 - tan 60​

2(1) - √3

=> 2 - √3

6 0
3 years ago
Read 2 more answers
b) The university gym opens at 9 am on Saturday mornings. One Saturday morning at 8:55 am there are 15 students outside the gym
max2010maxim [7]

Answer:

The complete question is:

At a university, 13% of students smoke.

a) Calculate the expected number of smokers in a random sample of 100 students from this university:

b) The university gym opens at 9 am on Saturday mornings. One Saturday morning at 8:55 am there are 27 students outside the gym waiting for it to open. Should you use the same approach from part (a) to calculate the expected number of smokers among these 27 students?

Part a is easy, because is a random sample, we can expect that just 13% of these 100 students to be smokers, and 13% of 100 is 13, so we can expect 13 of those 100 students to be smokers.

b) This time we do not have a random sample, our sample is a sample of 15 students who go to the gym in the early morning, so our sample is biased. (And we do not know if this bias is related to smoking or not, and how that relationship is), so we can't use the same approach that we used in the previous part.

3 0
3 years ago
-x-5y-5z=2<br> 4x-5y+4z=19<br> x+5y-z=-20
Leno4ka [110]
(x,y,z) = (-2, -3, 3)
8 0
3 years ago
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