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Neporo4naja [7]
3 years ago
9

How do you work out the range in a dot plot

Mathematics
1 answer:
son4ous [18]3 years ago
7 0

Answer:

By examining the line plot, we find the number with the maximum number of crosses or occurrences. This gives the mode of the data set. We find the smallest and the largest number from the data set and find their difference and this difference is the range of the given data set.

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Vanessa deposited money into a bank account that earned 1.25% simple interest each year. After 1/2 year, she had earned $5.00 in
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$800 :P
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3 years ago
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Graph f(x) = 22 +1 and g(x) = -x +4 on the same graph
Virty [35]

Answer:

-19 = x

Step-by-step explanation:

22 + 1 = -x + 4

23 = -x + 4

- 4 - 4

________

19 = −x

-19 = x

I am joyous to assist you anytime.

7 0
3 years ago
D(n)=6-4(n-1) Find the fifth term in the sequence
LiRa [457]

Answer:

5th term: -10

Step-by-step explanation:

To find the nth term in the sequence, you can substitute n into the equation:

d(n) = 6 - 4(n - 1)

Since we want the 5th term, we substitute 5:

d(5) = 6 - 4(5 - 1)

d(5) = 6 - 4(4)

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6 0
3 years ago
✓<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B19%20%2B%20%20%5Csqrt%7B30%20%2B%20%20%5Csqrt%7B32%20%2B%20x%20%20%7D%20%7D%
Setler79 [48]

We'll have to repeatedly square both sides of the equation, in order to get rid of the square roots. Squaring a first time yields

19+\sqrt{30+\sqrt{32+x}}=25

Move the 19 to the right hand side:

\sqrt{30+\sqrt{32+x}}=6

And square again:

30+\sqrt{32+x}=36 \iff \sqrt{32+x}=6

Square one last time:

32+x=36 \iff x=36-32=4

Let's check the solutions: all these squaring might have created external solutions:

\sqrt{19+\sqrt{30+\sqrt{32+4}}}=\sqrt{19+\sqrt{30+6}}=\sqrt{19+6}=\sqrt{25}=5

So, x=4 is a feasible solution.

8 0
3 years ago
8. The ratio of the number of model
disa [49]

Answer:

48

Step-by-step explanation:

36 divided by 3 times 4.

7 0
3 years ago
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