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Kitty [74]
3 years ago
5

Jasmine can run 4 5/6 miles in 2/3 of an hour. how many miles can she run 1 hour simplify comepletly

Mathematics
1 answer:
Vikentia [17]3 years ago
7 0

Remark

the question depends on d= r * t

d = the distance in miles.

r = the rate of travel in miles per hour

t = the time in hours.


Step One

Rearrange the formula so you are solving for the rate.


d = r * t Divide by t

4 5/6 = (4*6 + 5)/6 = 29/6


r = d / t


Step Two

Substitute into the equation.

r = \dfrac{\dfrac{29}{6}}{\dfrac{2}{3} }


Step Three

Turn the bottom fraction upside down. Multiply these two together.


r = \dfrac{29}{6} * \dfrac{3}{2}


r = 29/4 miles hour.


Step Four

Solve for d when t = 1 hour.


d = ??

r = 29/4 miles / hour

t = 1 hour.


d = 29/4 * 1

d = 29/4 miles


That's as simple as you can get it unless you want 7 1/4 miles or 7.25 miles


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Answer:

135°

Step-by-step Explanation:

==>Given:

An inscribed quadrilateral ABCD with,

m<A = (3x +6)°

m<C = (x + 2)°

==>Required:

measure of angle A

==>Solution:

First, let's find the value of x.

Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.

Therefore, this means m<A + m<C = 180°

Thus, (3x+6) + (x+2} = 180

3x + 6 + x + 2 = 180

Collect like terms:

3x + x + 6 + 2 = 180

4x + 8 = 180

Subtract 8 from both sides:

4x + 8 - 8 = 180 - 8

4x = 172

Divide both sides by 4:

4x/4 = 172/4

x = 43

We can now find m<A = (3x + 6)°

m<A = 3(43) + 6

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6 0
3 years ago
A group of 6 students is surveying their classmates to get feedback about different clubs they're involved in. If each surveys m
galben [10]

Answer:

The domain would be given by <u>D = {X ≥ 2} X = [2, Z].</u> Since the variable Z is the number of children in the school. And the 6 children should not survey the same person, it would be Z / 6 for each interviewer.

Step-by-step explanation:

- If the group of children surveys more than 2 classmates, it means that the number with which the survey begins is 12 students.

And since the maximum number of students in the school is given by the variable of Z, then Z is the number with which the domain closes.

The rank would be given by the set of [2, Z]

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astra-53 [7]

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f(x) = (x+3)(x-5) = x² - 2x - 15 = (x² - 2x + 1) - 1 - 15 = (x-1)² - 16

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