Answer:
E
Step-by-step explanation:
dy/dt = y² − 1
When -1 < y < 1, dy/dt is negative. So the solution is decreasing between y = -1 and y = 1.
Only one graph is consistently decreasing in that range, and that's the last graph.
Answer:
A 3√4
Step-by-step explanation:
The 3 stays and 16 gives you 4 and 4 becomes positive
.27 repeating.... you have to put three on the inside and 11 outside, so 11 goes into 3 zero times so put a zero at the top. Write a zero underneath and subtract 3-0 (obviously 3) and put a decimal point after the first three under the sign and the 0 above it. Add a zero after the threes decimal, and carry it down to the bottom most 3 to have 30. 11 goes into 30 two times so write a 2 at the top. Subtract the 30-22 at the bottom and get 8. Add another 0 after the 3 ( so now 3.00) and carry it to the 8 (80). 11 goes in 7 times, 77. So 7 on top and 80-77= 3 below. Add another zero to repeat process if necessary, but otherwise it repeats, just so you know ;) hope this helps
<span>if v belongs to V, then we can find scalars a1,a2,...,an, such that
v=a1*v1+a2*v2+...+an*vn,
L1(v)=L1(a1*v1+a2*v2+...+an*vn)
=a1*L1(v1)+a2*L1(v2)+...+an*L1(vn)
=a1*L2(v1)+a2*L2(v2)+...+an*L2(vn)
=L2(a1*v1+a2*v2+...+an*vn)
=L2(v)</span>
