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3 years ago

The following points for a function are graphed in the coordinate plane: (1, 2), (3, 8), (4, 11), and (6, 17).

Mathematics

1 answer:

aleksley [76]3 years ago

4 0

Answer: y=2x
I upload I picture of showing my work. Hope this help you.

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Please help me with this!!

Kaylis [27]

Answer:

C. 72

Step-by-step explanation:

So imagine every straight line you see equals to 180 degrees, so given one side of the angle...180 - 108 = 72

7 0

3 years ago

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Solve x'=5t(sqrt(x)) x(0)=1

LekaFEV [45]

Answer:

$2\sqrt{x}=\frac{5t^2}{2}+2$

Step-by-step explanation:

Given: $\frac{\mathrm{d} x}{\mathrm{d} t}=5t\sqrt{x}\,,\, x(0)=1$

Solution:

A differential equation is said to be separable if it can be written separately as functions of two variables.

Given equation is separable.

We can write this equation as follows:

$\frac{dx}{\sqrt{x}}=5t\,dt$

On integrating both sides, we get

$\int \frac{dx}{\sqrt{x}}=\int 5t\,dt$

Formulae Used:

$\int \frac{1}{\sqrt{x}}=2\sqrt{x}\,\,,\,\,\int t\,dt=\frac{t^2}{2}$

So, we get solution as $2\sqrt{x}=\frac{5t^2}{2}+C$

Applying condition: x(0) = 1, we get $C=2$

Therefore, $2\sqrt{x}=\frac{5t^2}{2}+2$

8 0

3 years ago

What is the area of the rectangle?

den301095 [7]

Answer:

$50\ units^{2}$

Step-by-step explanation:

Plot the figure to better understand the problem

see the attached figure

we know that

If the figure is a rectangle

then

$AB=CD \\AD=BC$

The area of the rectangle is equal to

$A=B*h$

where

B is the base

h is the height

the base B is equal to the distance AB

the height h is equal to the distance AD

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-5,5)\\B(0,-5)$

substitute the values

$d=\sqrt{(-5-5)^{2}+(0+5)^{2}}\\d=\sqrt{(-10)^{2}+(5)^{2}}\\dAB=\sqrt{125}\ units$

Step 2

Find the distance AD

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-5,5)\\D(-1,7)$

substitute the values

$d=\sqrt{(7-5)^{2}+(-1+5)^{2}}\\d=\sqrt{(2)^{2}+(4)^{2}}\\dAD=\sqrt{20}\ units$

Step 3

Find the area of the rectangle

$A=AB*AD$

we have

$dAB=\sqrt{125}\ units\\dAD=\sqrt{20}\ units$

substitute

$A=\sqrt{125}*\sqrt{20}\\A=\sqrt{2,500}\\A=50\ units^{2}$

7 0

3 years ago

Help me plz ITS URGENT

12345 [234]

The slope perpendicular is 2/3

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3 years ago

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Please help quickly!

Stells [14]

AB is reflected across the line Y=x

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3 years ago