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Nataliya [291]
3 years ago
12

What would be the measure of the exterior angle for each vertex of an equilateral triangle?

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0

Step-by-step explanation:

The exterior angles of an equilateral triangle will always have a measure of 120°.

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Answer:

Q1:  p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{8} \hspace{1mm}  \textbf{=} \hspace{1mm} \textbf{3}

We solve this taking LCM.

We get: $ \frac{-p - 24}{3} = 3 $

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$ \implies \textbf{p} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 33} $

Q4: $ \frac{\textbf{d}}{\textbf{11}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{4} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Again we proceed like Q1 by taking LCM.

We get: $ \frac{d - 44}{11} = - 13 $

$ \implies d - 44 = - 13 \times 11 = - 143 $

$ \implies d = - 143 + 44 $

$ \implies \textbf{d} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 99} $

Q7: 5t + 12 = 4t - 1

We club the like terms on either side.

$ \implies 5t - 4t = - 1 - 12 $

$ \implies (5 -4)t = - 13 $

$ \implies \textbf{t} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

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