Question

The depth of a lake in Lexington changes over time due to rainfall and evaporation. A few months ago, the depth was 1,300 feet. Currently, the depth is 1,547 feet. By what percent has the depth of the lake increased?

Answer 1

Answer:

The Depth of the lake had increased by 19%.

Step-by-step explanation:

Given:

Depth of lake few months ago = 1300 ft

depth of lake currently = 1547 ft

We need to find the percent of increase in depth of lake.

Solution:

First we will find the increase in depth of lake.

Increase in depth of lake can be calculated by subtracting Depth of lake few months ago from depth of lake currently.

framing in equation form we get;

increase in depth of lake = $1547-1300= 247\ ft$

Now to find the percent of increase in depth of lake we will divide  increase in depth of lake from Depth of lake few months ago and then multiply by 100.

framing in equation form we get;

percent of increase in depth of lake = $\frac{247}{1300}\times 100 = 19\%$

Hence the Depth of the lake had increased by 19%.