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Olegator [25]
3 years ago
15

Find the value of x if P Q R S spaceis a parallelogram.

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

The value of x is 15.

Step-by-step explanation:

Given

PQRS is a parallelogram.

∠Q = (3x + 25)°

∠S = (5x - 5)°

To determine

The value of x = ?

We know that both pairs of opposite angles of a parallelogram are congruent.

As ∠Q and ∠S are opposite angles of a parallelogram. Therefore,  ∠Q and ∠S are equal.

Thus,

∠Q = ∠S

substitute ∠Q = (3x + 25)° and ∠S = (5x - 5)° in the equation

(3x + 25)°  = (5x - 5)°

subtract 25 from both sides

3x + 25 - 25 = 5x - 5 - 25

3x = 5x - 30

flip the equation

5x - 30 = 3x

add 30 to both sides

5x - 30 + 30 = 3x + 30

5x = 3x + 30

subtract 3x from both sides

5x - 3x = 3x + 30 - 3x

2x = 30

divide both sides by 2

2x/2 = 30/2

x = 15

Therefore, the value of x is 15.

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4 0
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Factor out the coefficient of the variable 1/2d+6
Dahasolnce [82]
1/2d+6=1/2(d+12)
Leaving us with 0.5 or 1/2
4 0
2 years ago
The graph of f(x) and g(x)=f(x) + k is shown on the coordinate plane.<br> k = _ ?
Alenkasestr [34]

Answer:

k = 10

Step-by-step explanation:

f(x) has been moved up 10 units to get g(x).  So, k = 10

6 0
2 years ago
A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the number of cakes sold per
HACTEHA [7]

Answer:

A) Revenue function = R(x) = (580x - 10x²)

Marginal Revenue function = (580 - 20x)

B) Fixed Cost = 900

Marginal Cost function = (300 + 50x)

C) Profit function = P(x) = (-35x² + 280x - 900)

D) The quantity that maximizes profit = 4

Step-by-step explanation:

Given,

The Price function for the cake = p = 580 - 10x

where x = number of cakes sold per day.

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

where x = number of cakes sold per day.

Please note that all the calculations and functions obtained are done on a per day basis.

A) Find the revenue and marginal revenue functions [Hint: revenue is price multiplied by quantity i.e. revenue = price × quantity]

Revenue = R(x) = price × quantity = p × x

= (580 - 10x) × x = (580x - 10x²)

Marginal Revenue = (dR/dx)

= (d/dx) (580x - 10x²)

= (580 - 20x)

B) Find the fixed cost and marginal cost function [Hint: fixed cost does not change with quantity produced]

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

The total cost function is a sum of the fixed cost and the variable cost.

The fixed cost is the unchanging part of the total cost function with changing levels of production (quantity produced), which is the term independent of x.

C(x) = 900 + 300x + 25x²

The only term independent of x is 900.

Hence, the fixed cost = 900

Marginal Cost function = (dC/dx)

= (d/dx) (900 + 300x + 25x²)

= (300 + 50x)

C) Find the profit function [Hint: profit is revenue minus total cost]

Profit = Revenue - Total Cost

Revenue = (580x - 10x²)

Total Cost = (900 + 300x + 25x²)

Profit = P(x)

= (580x - 10x²) - (900 + 300x + 25x²)

= 580x - 10x² - 900 - 300x - 25x²

= 280x - 35x² - 900

= (-35x² + 280x - 900)

D) Find the quantity that maximizes profit

To obtain this, we use differentiation analysis to obtain the maximum point of the Profit function.

At maximum point, (dP/dx) = 0 and (d²P/dx²) < 0

P(x) = (-35x² + 280x - 900)

(dP/dx) = -70x + 280 = 0

70x = 280

x = (280/70) = 4

(d²P/dx²) = -70 < 0

Hence, the point obtained truly corresponds to a maximum point of the profit function, P(x).

This quantity demanded obtained, is the quantity demanded that maximises the Profit function.

Hope this Helps!!!

8 0
2 years ago
What is equivalent to 5(x + 12)<br><br> A x +12<br> B 2x - 60<br> C 5x + 60<br> D 2x - 60
Alex73 [517]

<u>Answer:</u>

\boxed{\boxed{\pink{\sf Option \ C \ is \ correct .}}}

<u>Step-by-step explanation:</u>

Given to us is , 5 ( x + 12 ) and we need to find which is its equivalent in the given options .

So,

\bf = 5 ( x + 12 ) \\\\=\bf 5x + 5\times 12 \\\\=\boxed{\red{\bf 5x + 60 }}

<h3><u>Hence</u><u> </u><u>opt</u><u>ion</u><u> </u><u>C </u><u>is</u><u> correct</u><u>.</u></h3>

4 0
2 years ago
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