The product of one term of a multiplicand and one term of its multiplier
1. Given that e<span>vents A and B are dependent, P(A)=20%, P(BIA)=25%. What is P(A and B)?
P(BIA)=[P(A and B)]/P(A)
it follows then that:
P(A and B)=P(A)*P(BIA)
P(A)=0.2
P(BIA)=0.25
hence
P(A and B)=0.2*0.25=0.05=5%
2. Given that </span><span> P(A) =12%, P(B)=48% and P(A or B)=50%. What is P(A and B)?
P(A or B)=P(A)+P(B)-P(A and B)
but
P(A)=12%, P(B)=48%, P(A and B)=50%
thus
P(A or B)=12%+48%-50%
simplifying the above we obtain:
P(A or B)=60%-50%=10%
</span>
The answer for blank #2 is 26
In order to at least earn $90, Katie can work exercising horses for 6 hours and cleaning stalls for 6 hours.
Step-by-step explanation:
Let hours of exercising horses be x --> $5 per hour = 5x
Let hours of cleaning stalls be y --> $10 per hour = 10y
Total earning = 
Total hours = 12
<u>Equation 1:</u>
5x + 10y = 
<u>Equation 2:</u>
x + y 
<em>1. Multiply equation 2 by -5</em>
x + y
(*-5)
5x + 10y = 
-5x - 5y
5x + 10y = 
<em>2. Solve</em>
-5x + 5x -5y + 10y = -60 + 90
5y = 30
y = 6
x + y = 12
x + 6 = 12
x = 6
Therefore, in order to at least earn $90, Katie can work exercising horses for 6 hours and cleaning stalls for 6 hours.
Keywords: Simultaneous, hours, equations
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Answer: 30
Step-by-step explanation:
Simple formula is
LCM*GCF=PRODUCT OF 2 NUMBERS
120 * 10 = 40 * x
1200 = 40x
x = 1200/40
x = 30