Since the probability of the coin landing leads is 1/2, simply cube 1/2 to arrive at your answer: 1/8.
You cube 1/2 because you must land heads three times in a row and each flip is independent from other flips.
Are there any options on the test or homework
Left side = 170-58 =121'
Bottom side = 96-4 =92'
Now let's calculate the upper oblique (slantwise) side by Pythagoras
oblique² = 92²+28² = 9248 & oblique =√9248 = 96.167'
The perimeter of the backyards = 96.167+93+92+121 = 402.167 ft
Answer:
the answer is 29/70
Step-by-step explanation:
Answer:
11. x = -3+√37 ≈ 3.08276
12. x = 11.2
13. x = -6 +6√5 ≈ 7.41641
Step-by-step explanation:
In each case, the relation of interest is ...
(distance to circle near) × (distance to circle far) = (distance to circle near) × (distance to circle far)
When there is only one point of intersection of the secant with the circle—because it is a tangent—then the product is the square of the length of the tangent.
11. 2(2+12) = x(x +6)
x² +6x -28 = 0
(x +3)² -37 = 0
x = -3+√37 ≈ 3.08276
12. 5(5+x) = 9(9)
5x +25 = 81
x = 56/5 = 11.2
13. x(x +12) = 12(12)
x² +12x -144 = 0
(x +6)² -180 = 0
x = -6 +√180 ≈ 7.41641
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<em>Comment on this secant rule</em>
This rule turns out to apply whether the point of intersection of the secant lines is outside the circle (as in these problems) or inside the circle (as in problem 9). The product of the two distances from the point of intersection to the circle is a constant for a given pair of intersecting secants/chords.
