1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ASHA 777 [7]
4 years ago
8

You work at a fruit stand that sells apples for $2 per pound, oranges for $5 per pound, and bananas for $3

Mathematics
1 answer:
kolezko [41]4 years ago
3 0
28lbs apples most, 14lbs bananas range, 18 bananas
You might be interested in
Why does the formula for finding the area of a circle work? A = π r²
Nadusha1986 [10]
The formula for finding the area of the circle works because they made it especially for it. I don’t really know how else to describe it, it simply just works.
7 0
4 years ago
Read 2 more answers
Two fifths times five
snow_lady [41]
\frac{2}5\times5=\frac{10}5=\boxed{2}

Note that the ÷5 and the ×5 cancel out.
7 0
3 years ago
Read 2 more answers
There are 9 yellow and 4 purple balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probab
anygoal [31]
9+4 = 13 total balls

1st pick would be 9/13 probability of picking yellow

2nd pick would be 4/13 probability

3rd pick would be 4/13 probability

 total probability : 9/13 * 4/13 * 4/13 = 144/2197

3 0
4 years ago
a) What is an alternating series? An alternating series is a whose terms are__________ . (b) Under what conditions does an alter
andriy [413]

Answer:

a) An alternating series is a whose terms are alternately positive and negative

b) An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|, converges if 0< b_{n+1} \leq b_n for all n, and \lim_{n \to \infty} b_n = 0

c) The error involved in using the partial sum sn as an approximation to the total sum s is the remainder Rn = s − sn and the size of the error is bn + 1

Step-by-step explanation:

<em>Part a</em>

An Alternating series is an infinite series given on these three possible general forms given by:

\sum_{n=0}^{\infty} (-1)^{n} b_n

\sum_{n=0}^{\infty} (-1)^{n+1} b_n

\sum_{n=0}^{\infty} (-1)^{n-1} b_n

For all a_n >0, \forall n

The initial counter can be n=0 or n =1. Based on the pattern of the series the signs of the general terms alternately positive and negative.

<em>Part b</em>

An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|  converges if 0< b_{n+1} \leq b_n for all n and \lim_{n \to \infty} b_n =0

Is necessary that limit when n tends to infinity for the nth term of bn converges to 0, because this is one of two conditions in order to an alternate series converges, the two conditions are given by the following theorem:

<em>Theorem (Alternating series test)</em>

If a sequence of positive terms {bn} is monotonically decreasing and

<em>\lim_{n \to \infty} b_n = 0<em>, then the alternating series \sum (-1)^{n-1} b_n converges if:</em></em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

then <em>\sum_{n=1}^{\infty}(-1)^{n-1} b_n  converges</em>

<em>Proof</em>

For this proof we just need to consider the sum for a subsequence of even partial sums. We will see that the subsequence is monotonically increasing. And by the monotonic sequence theorem the limit for this subsquence when we approach to infinity is a defined term, let's say, s. So then the we have a bound and then

|s_n -s| < \epsilon for all n, and that implies that the series converges to a value, s.

And this complete the proof.

<em>Part c</em>

An important term is the partial sum of a series and that is defined as the sum of the first n terms in the series

By definition the Remainder of a Series is The difference between the nth partial sum and the sum of a series, on this form:

Rn = s - sn

Where s_n represent the partial sum for the series and s the total for the sum.

Is important to notice that the size of the error is at most b_{n+1} by the following theorem:

<em>Theorem (Alternating series sum estimation)</em>

<em>If  \sum (-1)^{n-1} b_n  is the sum of an alternating series that satisfies</em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

Then then \mid s - s_n \mid \leq b_{n+1}

<em>Proof</em>

In the proof of the alternating series test, and we analyze the subsequence, s we will notice that are monotonically decreasing. So then based on this the sequence of partial sums sn oscillates around s so that the sum s always lies between any  two consecutive partial sums sn and sn+1.

\mid{s -s_n} \mid \leq \mid{s_{n+1} -s_n}\mid = b_{n+1}

And this complete the proof.

5 0
4 years ago
Find the shaded area of the circle below.
Crazy boy [7]

Answer:

area of the circle,

radius=10m

diameter=20m

πr²

3.14×100

314m²

area of the triangle=1/2×20×10

=100

area of the shaded area=314-100=214 m²

the answer is option <em>H</em>

6 0
3 years ago
Other questions:
  • What are the fractions One and five-sixths and Two and one-fourth written with a common denominator?
    14·1 answer
  • Whats the area of this shape
    12·1 answer
  • How is inductive reasoning used to recognize mathematical relationships?
    6·1 answer
  • Jan walks 40 meters in 15 seconds what is her rate?
    11·1 answer
  • 5/4623<br> Please I need answers as soon
    14·1 answer
  • Find the median<br><br> 11,19,7,37,17,24,6,1,15,23,12,2,10,3,14
    7·2 answers
  • <img src="https://tex.z-dn.net/?f=x1%2B2x2-x3%3D3%2C%202x1%2Bx2-2x3%3D1%2C%203x1%2B4x2-5x3%3D5" id="TexFormula1" title="x1+2x2-x
    5·1 answer
  • Z = -3a + 1<br><br> Solve for a<br><br> Thanks
    14·1 answer
  • Find the missing values in the ratio table. Then write the equivalent ratios.
    6·2 answers
  • Help please! thank you
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!