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ycow [4]
3 years ago
12

Answer quickly! It very urgent

Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer: Because the graphs of the two equations overlap each other

Step-by-step explanation:

Every point on the first line also satisfies the second equation.

This is the same as equivalent fractions

where 1/2 = 2/4 = 3/6 = 4/8

Graphing these on a number line would only show one dot.

You might be interested in
How do i solve with two variables
Verdich [7]
50 divided by 13 on both sides
13y/13 =0 50/13 = 3.846153....
change it to y= 3 since 4 is to big.
3•13 = 39
50-39=11
x=11


Final answer
x=11
y=3
6 0
3 years ago
In a group of 120 students,68 had riddena bus,78 had ridden the LRT,20 had riddenthe bus and the jeep ,19 had ridden the LRT and
Tju [1.3M]

Answer:

180

Step-by-step explanation:

4 0
3 years ago
In AEFG, the measure of ZG=90°, the measure of ZF=13°, and GE = 40 feet. Find the
kirza4 [7]

Answer: 173.3 feet

Step-by-step explanation:

3 0
3 years ago
What is the maximum volume in cubic inches of an open box to be made from a 12-inch by 16-inch piece of cardboard by cutting out
Romashka-Z-Leto [24]

If you start with a 12x16 rectangle and cut square with side length x, when you bend the sides you'll have an inner rectangle with sides 12-2x and 16-2x, and a height of x.

So, the volume will be given by the product of the dimensions, i.e.

(12-2x)(16-2x)x = 4x^3-56x^2+192x

The derivative of this function is

12x^2-112x+192

and it equals zero if and only if

12x^2-112x+192=0 \iff x = \dfrac{14\pm 2\sqrt{13}}{3}

If we evaluate the volume function at these points, we have

f\left(\dfrac{14-2\sqrt{13}}{3}\right) = \dfrac{64}{27}(35+13\sqrt{13})> f\left(\dfrac{14-2\sqrt{13}}{3}\right) = -\dfrac{64}{27}(13\sqrt{13}-35)

So, the maximum volume is given if you cut a square with side length

x=\dfrac{14-2\sqrt{13}}{3}\approx 2.7

5 0
3 years ago
A camera manufacturer spends $1500 each day for overhead expenses plus $9 per camera for labor and materials. The cameras sell f
Reil [10]

Answer:

a)The company has to 250 cameras in one day to equal its daily cost

b)Their daily profit  will be $400

Step-by-step explanation:

Given:

overhead expenses = $1500

labour and materials expenses = $9

cameras sell for $15 each

To Find:

(a)How many cameras must the company sell in one day to equal its daily cost

(b) If the manufacturer can increase production by 50 cameras per day, what would their daily profit be?

Solution:

a) let the number of cameras sold per day be x

Total daily cost = overhead expenses +labour and materials expenses

Total daily cost = 1500 + 9x--------------------------(1)

Total daily revenue = 15x------------------------------(2)

Equating (1) and (2)

1500 + 9x = 15x

1500 = 15x- 9x

1500 = 6x

x= \frac{1500}{6}

x= 250

So, the company has to 250 cameras in one day to equal its daily cost.

b) increasing production by 50 cameras per day will give a daily profit of

=>50 X (17-9)

=>50 X 8

=> 400

5 0
3 years ago
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