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charle [14.2K]
3 years ago
9

For the equation 8x + 2y = 16 What is the slope? What is the y-intercept (write as an ordered pair)? What is the x-intercept (wr

ite as an ordered pair)?​
Mathematics
2 answers:
kirza4 [7]3 years ago
8 0

Answer:

Slope= -4 y-intercept=(0,8). x-intercept=(2,0)

Step-by-step explanation:

2y= -8x+16

y= -4x+8

Use desmos so you can see it graphed out

LiRa [457]3 years ago
6 0

Answer:

y= -4x+16, (4,0), (0, 8)

Step-by-step explanation:

Let us rewrite the equation in slope intercept form, y=mx+b, where m is the slope:

2y= -8x+16

y= -4x+16

Therefore, -4 is the slope.

The x intercept can be found if we substitute 0 into the y:

0= -4x+16

4x=16

x=4

(4,0)

The y intercept can be found if we substitute 0 into the x:

2y= -8*0 +16

2y=0+16

2y=16

y=8

(0,8)

<em>I hope this helps! :)</em>

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These marks are used in geometry to symbolize congruence. If two sides or two angles are congruent, they are assigned with the same symbol.

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Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

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Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

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Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
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By Evaluating the Compound Interest, we come to know that Rajesh will have enough money in the account to cover all of the required loan payments.

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Now, we have

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Yes, he will have enough money in the account to cover all of the required loan payments.

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3 years ago
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