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Strike441 [17]
3 years ago
15

The sum of three consecutive integers is 177. What are the integers

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

57, 59, 61

Step-by-step explanation:

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The area of a square is 64 square units. How many units long is each of its sides?
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<h2>Area of a square = side × side</h2>

Let the side = x

{x}^{2}  = 64 \\ x =  \sqrt{64}  \\ x = 8

<h3>Length of each side = <u>8</u><u> </u><u>units</u></h3>

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What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

4 0
3 years ago
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