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borishaifa [10]

2 years ago

10

In triangle JKL, the length of side JK is 12 feet, and the length of side KL is 15 feet. Which of the following could be the len

gth of side JL?
A.
27 feet
B.
30 feet
C.
3 feet
D.
4 feet

1 answer:

Andrei [34K]2 years ago

8 0

Answer:

D

Step-by-step explanation:

every 2 sides of a triangle has to be bigger than the 3rd side

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kogti [31]

To prove that triangles TRS and SUT are congruent we can follow these statements:

1.- SR is perpendicular to RT: Given

2.-TU is perpendicular to US: Given

3.-Angle STR is congruent with angle TSU: Given.

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11 months ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

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1 year ago