530(1+.144/12)(.06) = 32.18 so even that is less than 35
So the answer is 31.80
Answer:
The critical value is T = 1.895.
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 8 - 1 = 6
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.895, which is the critical value.
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159
The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761
The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761
Hello from MrBillDoesMath!
Answer: x = 7/10
Discussion:
To eliminate fractions multiply each side by 10:
10 ( 9/5x - 2/5 ) = 10 * ( 8x +3)/10 or
10 * ( 9/5)x - 10 *(2/5) = 8x + 3 or
9 *2 x - 2*2 = 8x +3 or
18x - 4 = 8x + 3. Subtract 8x for each side:
18x - 8x - 4 = (8x - 8x) + 3 or
10x -4 = 0x + 3 or
10x -4 = 3 or
10x = 7
x = 7/10
Thank you,
MrB