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Oksi-84 [34.3K]
3 years ago
13

Construction viable argument. is 10% of 10% of 100 the same as 20% of 100​

Mathematics
1 answer:
IgorC [24]3 years ago
7 0

Answer:

no

10% of 100 is 10. 10% of 10 is 1.

20% of 100 is 20.

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Suppose that you draw two cards from a deck. After drawing the first card, you do not put the first card back in the deck. What
S_A_V [24]

Answer:

(B) 0.0588

Step-by-step explanation:

The probability is calculated as a division between the number of possibilities that satisfy a condition and the number of total possibilities. Then, the probability that the first card is diamonds is:

P_1=\frac{13}{52}

Because the deck has 52 cards and 13 of them are diamonds.

Then, if the first card was diamonds, the probability that the second card is also diamond is:

P_2=\frac{12}{51}

Because now, we just have 51 cards and 12 of them are diamonds.

Therefore, the probability that both cards are diamonds is calculated as a multiplication between P_1 and P_2. This is:

P=\frac{13}{52}*\frac{12}{51}=\frac{1}{17}=0.0588

8 0
3 years ago
A company considers buying a machine to manufacture a certain item. When tested, 28 out of 600 items produccd by the machine wer
weqwewe [10]

Answer:

The p-value of the test is 0.9918 > 0.05, which means that we fail to reject H_0, as we do not have enough evidence to say that defect rate of machine is smaller than 3%.

Step-by-step explanation:

The null and alternate hypothesis are:

H0:p≥0.03

Ha:p<0.03

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.03 is tested at the null hypothesis:

This means that \mu = 0.03, \sigma = \sqrt{0.03*0.97}

28 out of 600 items produced by the machine were found defective.

This means that n = 600, X = \frac{28}{600} = 0.0467

Value of the test-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.0467 - 0.03}{\frac{\sqrt{0.03*0.97}}{\sqrt{600}}}

z = 2.4

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.0467, which is the p-value of z = 2.4.

Looking at the z-table, z = 2.4 has a p-value of 0.9918.

The p-value of the test is 0.9918 > 0.05, which means that we fail to reject H_0, as we do not have enough evidence to say that defect rate of machine is smaller than 3%.

7 0
3 years ago
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3 years ago
Find the area of the triangle below.
fenix001 [56]

Answer:

area of a triangle is 1/2×h×b

Step-by-step explanation:

1÷2×12×13

=78

5 0
3 years ago
3w-4z=8<br> 2w+3z=-6 solve
marissa [1.9K]

Answer:

W = 0

Z = -2

Step-by-step explanation:

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