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hjlf
3 years ago
11

WILL GIVE BRAINLIEST

Mathematics
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

B  the service fee for coming to look at the machine

Step-by-step explanation:

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5tanx-2cotx+1=0...... .
Verdich [7]

Step-by-step explanation:

5(tanx)^2 -2 +tanx=0

let tanx=y

5y^2 + y-2=0

y=0.5403 or y= -0.7403

tanx=0.5403

x=arctan(0.5403)

x=28.38°

or

tanx=-0.7403

x=arctan(-0.7403)

x=143.49°

7 0
2 years ago
Please asap<br>for 10 points!​
kari74 [83]
<h3>Given:</h3><h3>Large cone:</h3>
  • r= 8 cm
  • h= 20 cm
<h3>Small cone:</h3>
  • r= 4 cm
  • h= 10cm
<h3>Note that:</h3>
  • r: radius
  • h: height
<h3>To find:</h3>
  • The volume of the frustum of the given cone.
<h3>Solution:</h3>
  • Frustum is a part of a cone formed by cutting off the top by a parallel plane.

\large\boxed{Formula: V= \frac{1}{3}\pi{r}^{2}h}

Let's solve!

First, let's find the volume of the smaller cone.

Substitute the values according to the

formula.

V= \frac{1}{3}×\pi×{4}^{2}×10

V= 167.5516082 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in the thousandths place is smaller than 5 so we won't have to round up.

\boxed{V= 167.55 \: {cm}^{3}}

Next, let's find the volume of the bigger cone.

Substitute the values according to the formula.

V= \frac{1}{3}×\pi×{8}^{2}×20

V= 1340.412866 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in thousandths place is smaller than 5 so we won't have to round up.

\boxed{V=1340.41 \: {cm}^{3}}

Now, we can find the volume of the frustum.

We'll have to minus the volume of the smaller cone from the bigger cone.

V= 1340.41-167.55

\large\boxed{V= 1172.86 \: {cm}^{3}}

<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>



8 0
1 year ago
Which of the following are not congruence theorems for right triangles? Check all that apply.
Lera25 [3.4K]

Answer:

c) HH E)AA

Step-by-step explanation:

Two right angles can be proved congruent by LA,LL,HA,HL properties.

HH and AA are not congruence property.

Two triangles can be proved similar by AA property. All congruent triangles are similar but all similar triangles are not similar.Hence right triangles can not be proved congruent by AA property.

Among the options given Option C and E are not congruence property.

7 0
3 years ago
Read 2 more answers
Need help l don’t understand
Diano4ka-milaya [45]

Step-by-step explanation:

open brackets and work out

6 0
2 years ago
Read 2 more answers
Please help! <br> what’s the value of x? <br> 8<br> 56<br> 12<br> 62
Katyanochek1 [597]
The value of x is 56
4 0
2 years ago
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