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hjlf
3 years ago
11

WILL GIVE BRAINLIEST

Mathematics
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

B  the service fee for coming to look at the machine

Step-by-step explanation:

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Show work please :: I forgot how to solve
Vesna [10]
40 pages = 80 minutes
210 pages = ? minutes
Well, take the first fact; 40 pages in 80 minutes and use it to find how many pages per minute.
40/80=1/2
1/2 pages = 1 minute
1 page = 2 minutes
210 pages = ? minutes
210*2=420
420 minutes = 7 hours
210 pages = 7 hours
Hope this helped :)
4 0
3 years ago
What do you need to know?
bulgar [2K]

wym are you asking a question?

6 0
4 years ago
Read 2 more answers
So far Monica has read 56 of a book she has read the same number of pages each day for five days what fraction of the book does
alexandr1967 [171]

Answer:

14/125

Step-by-step explanation:

56 % ÷ 5 days ie 11.2% per day ie 112/1000 or 14/125

4 0
2 years ago
PLEASE HELP ASAPPPPPO
Afina-wow [57]

Answer:

x=60

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2
Agata [3.3K]
\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------

\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left(  \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o
8 0
3 years ago
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