Answer:
$87,461
Step-by-step explanation:
Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft
where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.
S = (119 + 147 + 190) / 2 = 456/ 2 = 228
Using Heron's formula which gives the area in terms of the three sides of the triangle
= √s(s – a)(s – b)(s – c)
Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)
=> √228 (109)(81)(38)
= √228(335502)
=√76494456
= 8746.1109071 * $10
= 87461.109071
≈$87,461
Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.
The answer is B. Because there is 2 multiples on 5 in 1-12; 5 and 10 so now you have 2/12 so simplify it to the lowest possible fraction. 1/6
Answer:
radius 2 meters
Step-by-step explanation:
Take the circumference formula 
Divide both sides by pi ÷ 3.14 ÷3.14
4=d
Divide by 2 to find radius 4 divided by 2 is 2
Answer:
constant for the first blank
liner equation=y-mx-b form
liner graph blank= straight
i forgot the other ones
Step-by-step explanation:
