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3 years ago

What is the solution to this linear system?

Mathematics

1 answer:

sashaice [31]3 years ago

5 0

Answer:

(2,7)

Step-by-step explanation:

The point where the two linear line intersect is the solution of this problem.

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A school is building a rectangular stage for its chorus. The stage must have a width of 4 feet. The area of the stage must be at

slavikrds [6]

Answer: Length ≥ 6 feet

Step-by-step explanation:

The area of a rectangle= length × width

In this case, the width is 4 feet and the area of the stage must be at most 24 square feet.

The inequality that describes the possible lengths (in feet) of the stage would be:

Length × Width ≥ 24

Length × 4 ≥ 24

Length ≥ 24/4

Length ≥ 6

Therefore, the length must be at most 6 feet.

4 0

3 years ago

Question 1

Effectus [21]

Answer:

Step-by-step explanation:

Substitute 3 in for m and solve

4m - 1 = 4(3) - 1 = 11

5m - 4 = 5(3) - 4 = 11

4 0

3 years ago

Read 2 more answers

What is the rate of change for 1

Alla [95]

Answer:

Option D, $24$

Step-by-step explanation:

<u>Step 1: Determine the rate of change or slope</u>

$m = \frac{y_2-y_1}{x_2-x_1}$

$m=\frac{32-8}{2-1}$

$m=\frac{24}{1}$

$m=24$

Answer: Option D, $24$

5 0

2 years ago

The sum of all lengths of polygon

alexdok [17]

I think the answer is The perimeter!

8 0

3 years ago

Six pyramids are shown inside of a cube. The height of the cube is h units. Six identical square pyramids can fill the same volu

MAXImum [283]

Answer:

(A)The height of each pyramid is One-half h units.

Step-by-step explanation:

Height of the Cube = h units

Volume of the Cube $=h^3 $ cubic units$

If Base of the cube =Base of the square pyramid

Base of the square pyramid = h units

$\text{Volume of a Pyramid}=\dfrac{1}{3}*Base Area*Height$

$\text{Volume of One Pyramid}=\dfrac{1}{3}*h^2*Height$

$\text{Volume of Six Pyramids}=6*\dfrac{1}{3}*h^2*Height\\=(2h^2*Height)\:cubic\:units$

Since Volume of the Cube = Volume of Six Square Pyramids

Then:

$2h^2*Height=h^3\\Height=\dfrac{h^3}{2h^2} \\$Height of each pyramid =\dfrac{1}{2}h \:Units$

5 0

3 years ago

Read 2 more answers