Answer:
Kevin's unit rate is 8.5. This means Kevin earns $8.5 ever hour.
Step-by-step explanation:
51.00/6.
Hope this helps! :)
Answer: a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
Step-by-step explanation:
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:
Since we have given that

Using the poisson process, we get that
(a) less than or equal to 12
probability= 
(b) equal to 13
probability=

(c) greater than 12
probability=

(d) equal to 20
probability=

(e) between 10 and 15, inclusively
probability=
Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
Answer:
Step-by-step explanation:
lets eliminate the parenthesis,
-2x-2=2x-2
-4x=0
x=0
$6.48- $6.00= $.48
.48÷ 6.0= 0.08
0.08 = 8%
tax rate is 8%
Answer:
least - 3 * 3 * 3
Step-by-step explanation:
3 * 3 * 3
9 * 3
27