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natka813 [3]
3 years ago
9

Find the perimeter of this question.

Mathematics
1 answer:
lilavasa [31]3 years ago
3 0
Finding the perimeter with all known sides is very easy. All you need to do is add up all of the sides. In this case the answer is 58 in. Hope this helps!
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Goshia [24]

Answer:

Step-by-step explanation:

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3 0
2 years ago
Can you give an example of equations when you are given the constant of proportionality?
aleksandr82 [10.1K]
Example:
Proportionality=1
5=5x
Divide both sides by 5 , and you get 1=x,
so the proportionality is 1
6 0
2 years ago
-1≤ 3x-10≤ 2 please help me
kicyunya [14]

Answer:

3 ≤ x ≤ 4

Step-by-step explanation:

Step 1: Add 10 to all parts/sections.

  • -1 + 10 \leq  3x - 10 + 10 \leq 2+10
  • 9\leq 3x\leq 12

Step 2: Divide all parts/sections by 3.

  • \frac{9}{3} \leq \frac{3x}{3} \leq \frac{12}{3}
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Therefore, the answer is 3 ≤ x ≤ 4.

5 0
2 years ago
Read 2 more answers
NEED HELP ASAP<br><br><br> Find f(-2) for f(x) = 2(4)^x
viktelen [127]

Answer:

A.) \frac{1}{8}

Step-by-step explanation:

f(-2) means plug in -2 in for x for the equation f(x), therefore,

f(-2) = 2(4)^x = 2(4)^{-2} = \frac{1}{8}

4 0
2 years ago
Find the zeros of the following polynomial functions, with their multiplicities. (a) f(x)= (x +1)(x − 1)(x² +1) (b) g(x) = (x −
larisa [96]

Answer:

a) zeros of the function are x = 1 and, x = -1

b) zeros of the function are x = 2 and, x = 4

c) zeros of the function are x = \frac{3}{2}

d) zeros of the function are x = \frac{-4}{3}  and, x = 17

Step-by-step explanation:

Zeros of the function are the values of the variable that will lead to the result of the equation being zero.

Thus,

a) f(x)= (x +1)(x − 1)(x² +1)

now,

for the (x +1)(x − 1)(x² +1) = 0

the condition that must be followed is

(x +1) = 0 ..........(1)

or

(x − 1) = 0 ..........(2)

or

(x² +1) = 0 ...........(3)

considering the equation 1, we have

(x +1) = 0

or

x = -1

for

(x − 1) = 0

x = 1

and,

for (x² +1) = 0

or

x² = -1

or

x = √(-1)         (neglected as it is a imaginary root)

Thus,

zeros of the function are x = 1 and, x = -1

b) g(x) = (x − 4)³(x − 2)⁸

now,

for the (x − 4)³(x − 2)⁸ = 0

the condition that must be followed is

(x − 4)³ = 0 ..........(1)

or

(x − 2)⁸ = 0 ..........(2)

considering the equation 1, we have

(x − 4)³ = 0

or

x -4 = 0

or

x = 4

and,

for (x − 2)⁸ = 0

or

x - 2 = 0

or

x = 2        

Thus,

zeros of the function are x = 2 and, x = 4

c) h(x) = (2x − 3)⁵

now,

for the (2x − 3)⁵ = 0

the condition that must be followed is

(2x − 3)⁵ = 0

or

2x - 3 = 0

or

2x = 3

or

x = \frac{3}{2}

Thus,

zeros of the function are x = \frac{3}{2}

d)   k(x) =(3x +4)¹⁰⁰(x − 17)⁴

now,

for the (3x +4)¹⁰⁰(x − 17)⁴ = 0

the condition that must be followed is

(3x +4)¹⁰⁰ = 0 ..........(1)

or

(x − 17)⁴ = 0 ..........(2)

considering the equation 1, we have

(3x +4)¹⁰⁰ = 0

or

(3x +4) = 0

or

3x = -4

or

x = \frac{-4}{3}

and,

for (x − 17)⁴ = 0

or

x - 17 = 0

or

x = 17        

Thus,

zeros of the function are x = \frac{-4}{3}  and, x = 17

7 0
3 years ago
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