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PtichkaEL [24]
4 years ago
11

Notice that this map has lines of longitude that are

Geography
2 answers:
Sav [38]4 years ago
6 0

Answer:

The answer is equal-area

Explanation:

I just got it correct on the assignment

Drupady [299]4 years ago
4 0

Answer:

equal-area

Explanation:

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Which best describes how ice cores are important to the study of geologic history?
Stolb23 [73]
many fossils can be preserved in the ice. as well as radiation levels. oxygen levels. carbon dioxide levels. and many more to determine the climate of the past.
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3 years ago
Read 2 more answers
. If the fastest passenger aircraft can fly 0.45 km/s (1000 mph), how long would it take to reach the sun? The galactic center?
nadezda [96]

Answer:

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The passenger aircraft would take 1.733\times 10^{10} years to reach the gallactic center.

Explanation:

The distance to the sun from the Earth is approximately equal to 1.496\times 10^{8}\,km, if the passenger travels at constant speed, then the time needed to reach the sun is calculated by the following kinematic formula:

\Delta t = \frac{s}{v} (1)

Where:

s - Travelled distance, measured in kilometers.

v - Speed of the passenger aircraft, measured in kilometers per second.

\Delta t - Travelling time, measured in seconds.

If we know that s = 1.496\times 10^{8}\,km and v = 0.45\,\frac{km}{s}, then the travelling time is:

\Delta t = \frac{1.496\times 10^{8}\,km}{0.45\,\frac{km}{h} }

\Delta t = 3.324\times 10^{8}\,s

\Delta t = 3847.736\,days

\Delta t = 10.542\,years

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The distance between the Earth and the galactic center is approximately equal to 2.460\times 10^{17}\,km. If the passenger travels at constant speed and if we know that s = 2.460\times 10^{17}\,km and v = 0.45\,\frac{km}{s} , then the travelling time is:

\Delta t = \frac{2.460\times 10^{17}\,km}{0.45\,\frac{km}{s} }

\Delta t = 5.467\times 10^{17}\,s

\Delta t = 6.327\times 10^{12}\,days

\Delta t = 1.733\times 10^{10}\,years

The passenger aircraft would take 1.733\times 10^{10} years to reach the gallactic center.

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3 years ago
Solutions to the limitations of water transportation​
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3. It is adversely affected by weather conditions.

4. Sea transport requires large investment on ship and their maintenance.

5. It has high maintenance costs for ship and takers as it requires constant repairs and painting of ships.

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How did Hurricane Katrina create both push and pull factors for migration into and out of New Orleans? A. The destruction caused
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The economy of central american is primarily based on what two thing?
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