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baherus [9]
3 years ago
9

What is the area of the resulting two dimensional cross section?

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0
A....if its wrong im sorry but i believe its a because you will do 4x4 and will get the sum of 16ft square 

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PLEASE HELP ME ASAP I REALLY NEED HELP!!!
padilas [110]

1) \overline{UP}

2) \overline{UP} \cong \overline{UP}

3) \overline{UR}

4) \overline{PR}

5) \triangle OUP \cong \triangle RUP by SSS

6) CPCTC

7 0
2 years ago
T(z)= sin^2(z/4), {-3 ≤ z ≤ 8}
Usimov [2.4K]

Answer:

T´(z)=n^2s/4*i

Step-by-step explanation:

T(z)=d/dz(sin^2*z/4)

T´(z)=d/dz(sn^2zi/4)

T´(z)=d/dz(sn^2z/4*i)

T´(z)i*d/dz(sn^2z/4)

T´(z)=n^2s/4*i

Simplify

3 0
3 years ago
Rewrite using a single positive exponent.<br> 7^9 x 7^-2
lidiya [134]

Answer:

7^7

Step-by-step explanation:

When you multiply exponents with the same base, you add the exponents

Hope it helped!

6 0
3 years ago
Given that the diameter of Circle A is 6 cm , and the radius of Circle B is 18 cm , what can be concluded about the two circles?
ELEN [110]

Answer:

The radius of circle B is 6 times greater than the radius of circle A

The area of circle B is 36 times greater than the area of circle A

Step-by-step explanation:

we have

<em>Circle A</em>

D=6\ cm

The radius of circle A is

r=6/2=3\ cm -----> the radius is half the diameter

<em>Circle B</em>

r=18\ cm

Compare the radius of both circles

3\ cm< 18\ cm

18=6(3)

The radius of circle B is six times greater than the radius of circle A

Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared

All circles are similar

In this problem the scale factor is 6

so

6^{2}=36

therefore

The area of circle B is 36 times greater than the area of circle A

8 0
3 years ago
The diagram shows a vertical tower DC on a horizontal ground ABC.
sasho [114]
The measure of ABD=180°- 54°=26°
and then the measure of ADB= x
and x + 26° + 28°= 180°, sum of anlgle in a triagle property
 it means x= 180°- 26-28=126°
application of sinus law in the triangle

sin 28 / BD = sin 126/ AD = sin 26/ 25 so we can deduce that 

AD= 25sin126 / sin26= 46.12
let 's consider the triangle ADC, so for finding h, we have sin 28 = h / AD
and then h = AD x sin28=21.65

<span>Calculate the height of the tower is 21.65</span>

6 0
3 years ago
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