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AlexFokin [52]
2 years ago
9

18

Mathematics
1 answer:
GalinKa [24]2 years ago
6 0

Answer:

18

ZAOC and ZCOB are supplementary angles.

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If [x] denotes the least integer greater than or equal to x and [x/2] = 0, which of the following could be the value of x?A. -2B
podryga [215]

Answer:

B) -3/2

Step-by-step explanation:

If [x/2]=0 then x/2 is a number such that the least integer greater than or equal to x/2 is 0. We can rewrite this as the inequality x/2≤0. Then, the value of x in C, D and E is wrong because they are positive numbers, then x/2 would be a positive number which contradicts this inequality.

Now, 0 is the least integer that satisfies this inequality, therefore we cannot have that x/2≤-1 since -1 is an integer and -1<0. Then x/2>-1. This discards A as wrong, because for x=-2, x/2=-1, contrary to x/2>-1.

Thus B is the right answer. To verify, if x=-3/2, then x/2=-3/4 and we have that -1<-3/4≤0 as required.

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\left\{\begin{array}{ccc}2x-3y=-27&|\cdot3\\-3x+2y=23&|\cdot2\end{array}\right\\\underline{\left\{\begin{array}{ccc}6x-9y=-81\\-6x+4y=46\end{array}\right}\ \ \ \ |\text{add both sides}\\.\ \ \ \ \ \ -5y=-35\ \ \ \ \ |:(-5)\\.\ \ \ \ \ \ \ \ y=7\\\\\text{put the value of y to the first equation}\\\\2x-3(7)=-27\\\\2x-21=-27\ \ \ \ |+21\\\\2x=-6\ \ \ \ |:2\\\\x=-3\\\\\text{Answer:}\ x=-3,\ y=7\to\boxed{(-3,\ 7)}

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