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Alexxx [7]
3 years ago
11

the population of a school is 400 students. Next year it is expected to be about 120% of what it is now. Choose next year's stud

ent population from the answers below. A.320 B.80 C.400 D.480
Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0
Given:
this year's population: 400 students
next year's population: 120% of this year's population

this year's population x rate of next year's population = next year's population

400 students * 120% = 480 students  CHOICE D.

There will be 480 students next year.


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the final price of the wind chime is $29.925 .

<u>Step-by-step explanation:</u>

Here we have , A home improvement store sold wind chimes for $30 each. A customer signed up for a free membership card and received a 5% discount off the price. Sales tax of 5% was applied after the discount. We need to find What was the final price of the wind chime . Let's find out:

Initially we have , 5% discount in $30 i.e.

⇒ (30(5))/100

⇒ (150)/100

⇒ $1.5 , So now price becomes $30 - $1.5 = $28.5 . At this amount there's 5% tax i.e.

⇒ (28.5(5))/100

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3 years ago
(Recall: 2.20lb = 1 kg)<br> 52 lb =___kg
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52lbs x 2.2kg = 114.4kg
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3 years ago
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5 0
3 years ago
Estimate √53 between two numbers to the tenths place.
ZanzabumX [31]

Answer:

  53 lies between 7.2² and 7.3²

Step-by-step explanation:

Estimating a root to the nearest tenth can be done a number of ways. The method shown here is to identify the tenths whose squares bracket the value of interest.

You have answered the questions of parts 1 to 3.

__

<h3>4.</h3>

You are given that ...

  7.2² = 51.84

  7.3² = 53.29

This means 53 lies between 7.2² and 7.3², so √53 lies between 7.2 and 7.3.

53 is closer to 7.3², so √53 will be closer to 7.3 than to 7.2.

7.3 is a good estimate of √53 to the tenths place.

_____

<em>Additional comment</em>

For an integer n that is the sum of a perfect square (s²) and a remainder (r), the square root is between ...

  s +r/(2s+1) < √n < s +r/(2s)

For n = 53 = 7² +4, this means ...

  7 +4/15 < √53 < 7 +4/14

  7.267 < √53 < 7.286

Either way, √53 ≈ 7.3.

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The root is actually equal to the continued fraction ...

  \sqrt{n}=\sqrt{s^2+r}=s+\cfrac{r}{2s+\cfrac{r}{2s+\dots}}

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12 12 12 12 12 12 12 its 12

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