The answer is: " (x² − 3) " .
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Explanation:
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Given: 3x² <span>− 9x ; factor out a "3x" ;
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</span>→ 3x (x² − 3) ;
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The answer is: " (x² − 3) " .
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9x^2 and 5x are not like terms because 9x is being squared and 5x isn't.
Answer:
1/8
Step-by-step explanation:
To find which bag weight Carla needs, the first step is to find the total weight of the bags shown in the line plot.
There are three -pound bags.
There are six -pound bags.
There are four -pound bags.
Multiply the weight and number of each bag to find the total weight of each different weight bag.
Now, add the three totals.
Finally, subtract the total weight from four pounds in order to find which weight Carla needs.
So, Carla should pick one -pound bag of candy to total four pounds.
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the
KM² = KE² + ME²KM² = 8² + (3√5)² = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM) = 1/2 * 3√5 * (40 + 24) = 1/2 * 3√5 * 64 = 3 x 2.23 * 32 = 214.66 units²