Ask question

Ask question

All categories

2 years ago

14

Mang Ambo was admitted to the hospital because his body temperature is 39.6ºC. How much higher is his temperature than the norma

l? A. What is asked? B. What is the operation to be used? C. Write the mathematical sentence? D. What is the answer?

1 answer:

Rudik [331]2 years ago

5 0

Answer:

2.6 degree Celsius

Step-by-step explanation:

A) It is asked that by how much degrees the temperature of Mang Ambo is higher than that of normal body temperature (37 degree Celsius) of human being

B) Subtraction operation will be used

C) Temperature higher than normal human body temperature

$= 39.6 -37\\$

D) $2.6$ degree Celsius

You might be interested in

Solve the polynomial inequality x^2-3x-10>0

djverab [1.8K]

As x² - 3x - 10 factors, we can use the zero product property and pull it apart into factors. It factors because 2 and 5 have a difference of 3 and product of 10

x² - 3x - 10 > 0

(x - 5)(x + 2) > 0

To find where the inequality is true, we use a sign test. When x-5 > 0, it means x >5, and 5 is one of our sign test values. Similarly, -2 is the other. We can then make three intervals - A (less than -2), B (between -2 and 5), and C (more than 5).

<--------------- -2 ------------------ 5 -------------------------->

A B C

To do a sign test, we choose values to see what happens. First, test x = -5.

(-5 - 5)(-5 + 2) = (-10)(-3) = 30. Because 30 > 0, the inequality is true for x < -2. So interval A is true.

Next, test x = 0.

(0 - 5) (0 + 2) = (-5)(2) = -10. Because -10 < 0 is false, the inequality is false for x > -2 and x < 5. So interval B is false.

Last, test x = 10

(10 - 5) (10 + 2) = (5) (8) = 40. Because 40 > 0 is true, the inequality is true for x > 5. So interval C is true.

We put the true intervals together.

(-∞, -2) ∪ (5, ∞) is where this inequality is true,

{x : x < -2 or x > 5} is also how it's said in set notation.

7 0

3 years ago

Which of the following equations describes the line shown below? Check all

Setler79 [48]

Answer:

y = -1/2 x + 2

Step-by-step explanation:

Which of the following equations describes the line shown below? Check all

that apply.

(-4, 4)

(2, 1)

The standard equation of a line is y = mx,+b

m is the slope

b is he y-inttercept

Get the slope

Slope m = y2-y1/x2-x1

Substitute the coordinate

M = 1-4/2-(-4)

M = -3/6

M = -1/2

Substitute m= -1/2 and (2,1) into y = mx+b

1 = -1/2(2)+b

1 = -1+b

b = 1+1

b=2

Get the equation

Recall y =mx+b

y = -1/2 x + 2

3 0

3 years ago

What is the distance between the points (2,10) and (-6, 4) on the coordinate

stellarik [79]

Answer:

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

Therefore distance s=10 units

Step-by-step explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is $s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ units

Let $(x_1,y_1)$ , $(x_2,y_2)$ be the given points (2,10) and (-6, 4) respectively

Now substituting the values in the distance formula we get

$s=\sqrt{(-6-2)^2+(4-10)^2}$

$=\sqrt{(-8)^2+(-6)^2}$

$=\sqrt{8^2+6^2}$

$=\sqrt{64+36}$

$=\sqrt{100}$

$=10$

Therefore s=10 units

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

5 0

3 years ago

The slope f′(x) at each point (x,y) on a curve y=f(x) is given, along with a point (a,b) on the curve. Use this information to f

Montano1993 [528]

$f'(x)=\dfrac{4x}{1+7x^2}$

Integrating gives

$f(x)=\displaystyle\int\frac{4x}{1+7x^2}\,\mathrm dx$

To compute the integral, substitute $u=1+7x^2$ , so that $\frac27\,\mathrm du=4x\,\mathrm dx$ . Then

$f(x)=\displaystyle\frac27\int\frac{\mathrm du}u=\frac27\ln|u|+C$

Since $u=1+7x^2>0$ for all $x$ , we can drop the absolute value, so we end up with

$f(x)=\dfrac27\ln(1+7x^2)+C$

Given that $f(0)=10$ , we have

$10=\dfrac27\ln1+C\implies C=10$

so that

$\boxed{f(x)=\dfrac27\ln(1+7x^2)+10}$

7 0

3 years ago

The absolute value of

MatroZZZ [7]

The correct answer is d

5 0

2 years ago