(105^3) * (105^3).....keep the base and add the exponents
In order to solve or know the probability of having 2 girls
and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s
triangle will be likely used. And we will be referring to the line 4 of pascal’s
triangle, which was 1 4 6 4 1. Then it
will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2
boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to
get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.
3 odd integers have a property that they average up to the middle large one. Let's say we have 3, 5, and 7. 3 is 2 less than 5 and 7 is 2 more than 5. so when you add them it equals 2 times 5.
After we know that, the sum of 3 odd integers is just 3 times the middle number. ex. 3+5+7 = 3 times 5 = 15
Then we know the some number times three = 225. we find out that the middle number is 75, so the other two are 73 and 77
There are 11 days until Richards's concert.
Susie's concert is 7 days after Richard's.
so Susie's concert: 11+7=18
answer
D. 11+7=18
for example lets use 3^2 + 4^2, you add the main numbers, 3 and 4 to get 7, then there are still the exponents, the squared signs, they don't change, they stay as a two. If your problem required a single whole number, then you have to square the 7, 7*7 is 49, so that or 7^2 would be your final answer.
