<u>Answer:
</u>
Expression x + 2my + z represents cost of order where x, y, z are cost of small , medium and large drinks (in dollars) respectively.
<u>Solution:
</u>
Given that
Juan’s family ordered a small drink and m medium drinks.
Alex family ordered m medium drinks and a large drink.
Need to write an algebraic expression which shows total cost of both order in dollars.
Let’s assume cost of one small drink = x
And assume cost of one medium drink = y
And assume cost of one large drink = z
So now cost of order of Juan’s family is equal to cost of 1 small drink + cost of m medium drinks = 1 
x + m y
= x + my
And cost of order of Alex family is equal to cost of m medium drinks + cost of one large drink
= m x y + 1 x z
=my + z
So total cost of both order in dollars = x + my + my + z = x + 2my + z
Hence expression x + 2my + z represents cost of order where x , y , z are cost of small , medium and large drinks (in dollars) respectively.
It’s C because through a Venn diagram C depicts both French and Spanish.
Answer:
All are 63
Step-by-step explanation:
m∠1 = 180 - 117 = 63 (linear pair)
m∠2 = 63 (alternate interior angle with ∠1)
m∠3 = m∠1 = 63 (isosceles triangle property)
Hope it helps :)
Please mark my answer as the brainliest
Answer:
Step-by-step explanation:
From the given information:
a) To express the weekly profit as a function of price
Cost =C(q) = 1500 + 10q
Revenue = p×q = (50 − 0.1q)×q = 50q - 0.1q²
Revenue = 50q - 0.1q²
Weekly profit = Revenue - Cost
P(q) = (50q -0.1q²) - (1500 + 10q)
P(q)= -0.1 q² + 40 q - 1500
However, q = 500 - 10 p using p = 50 − 0.1q
P= -0.1 (500 - 10 p)² + 40 (500 - 10 p) - 1500
P= -10 p² + 600 p - 6500
b)
The price at which the bottle of the wine must be sold to realise a maximum profit can be determined by finding the derivative and then set it to 0
P' = 0
= -20p+600 = 0
20p = 600
p = 600/20
p = $30
c)
The maximum profit that can be made by the producer is:
P= -10(30)² + 600(30) - 6500
P = - 9000 + 18000 - 6500
P = $2500
Lets find out...
our fraction is 1/2.....
when the numerator is increased by 20%......1 + 0.20(1) = 1.2
when the denominator is increased by 50%....2 + 0.50(2) = 3
1/2 = 0.5....original fraction
1.2 / 3 = 0.4.....increased fraction
decrease = (original number - new number) / original number...* 100
= (0.5 - 0.4) / 0.5...* 100
= (0.1 / 0.5)....* 100
= 0.2 * 100
= 20% decrease <====
