Answer: 0.135
Step-by-step explanation:
if 54 % of internet users have a wireless connection then number of people that do nor have a wireless connection =46%.
Let A be the event that 54% of internet users have wireless connection.
Let B be the event that 25% of these users that have internet connection use twitter to share updates about themselves.
Hence, probability of A and B happening becomes:
P(AnB) = P(A) * P(B)
P(AnB) = 0.54 * 0.25
P(AnB) = 0.135
Assuming the pilcrow is supposed to represent pi:

100
According to the empirical rule, roughly 68% of the scores fall between z = -1 and z = 1
You can use a calculator to get a more approximate answer. If you have a TI calculator, you can use the "normalcdf" function to type in normalcdf(-1,1)