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3 years ago

Pls help. even if it’s just one question

Mathematics

1 answer:

Yanka [14]3 years ago

6 0

Answer:

a, (5;1) R = $\sqrt{7}$

b, (-2; 4) R = $2\sqrt{2}$

c, (4;7) R = 7

d, (-3; -6) R = 7

Step-by-step explanation:

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Please help me ASAP it’s times THANK U

goblinko [34]

Answer:

Only choices C and D are solutions

Step-by-step explanation:

6x + 3y = -15

y = -2x - 5

6x + 3y = -15

6x + 3(-2x - 5) = -15

6x - 6x - 15 = -15

0 = 0

Since 0 = 0 is a true statement, both equations of this system are the same equation and represent a single line on the coordinate plane.

We need to check each choice in just one equation.

Let's use the second equation.

y = -2x - 5

(2, 7)

7 = -2(2) - 5

7 = -4 - 5

7 = -9 False

Not a solution

(5, 0)

0 = -2(5) - 5

0 = -10 - 5

0 = -15 False

Not a solution

(-3, 1)

1 = -2(-3) - 5

1 = 6 - 5

1 = 1 True

Solution

-13 = -2(4) - 5

-13 = -8 - 5

-13 = -13 True

Solution

Answer: Only choices C and D are solutions

7 0

3 years ago

1/2 to the power of 5 equals

svp [43]

Answer:

1/32

Step-by-step explanation:

This could be written as $1/2^5\\$

1/2 x 1/2 x 1/2 x 1/2 x 1/2

= 1/32, or 0.03125.

3 0

2 years ago

Is PRB congruent to QSB? Justify your answer.

Serhud [2]

Answer:

When looking at this model, and asking yourself the question, is PRB congruent to QSB? PRB is in fact congruent to QSB. Congruent means that two figures have the same shape/size, no matter if it's mirrioring or not it is congruent. In this image, PRB is one shape, and QSB is another. They have the exact same points and they're also the same shape, but one is flipped the right side up. It was also stated PQ and RS bisect eachother at point B, <p is congruent to <Q, and <R is congruent to <S proving all these connections make this figure conguent.

Step-by-step explanation:

8 0

2 years ago

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

Which of the following points lies on the graph of the inverse of f(x) = 6^(x + 1)?

svetlana [45]

F ( x ) = 6^(x+1)
y = 6^(x+1)
$x+1=log _{6}y \\ x = log _{6}y-1$
The inverse is:
$y = log _{6}x$
And when you plug in the values: x = 1, y = - 1:
- 1 = log 1 - 1
- 1 = 0 - 1
- 1 = - 1
so the answer is:
( 1, - 1 )

8 0

3 years ago