Question

The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim? Show your work.

Answer 1

Diameter of the basketball rim = 18 inches

Circumference of the standard basketball = 30 inches

Area of circle = π r²  

Basketball rim = 3.14 * (18/2)² = 3.14 * 9² = 3.14 * 81 = 254.34 in²

Circumference of a circle = 2 π r

30 = 2 * 3.14 * r

r = 30 / (2*3.14) = 30 / 6.28 = 4.78 inches

Standard basketball = 3.14 * (4.78)² = 3.14 * 22.85 = 71.75 in²

254.34 - 71.75 = 182.59 in²

Answer 2

Answer:

4.2 inches

Step-by-step explanation:

Basketball rim:

diameter = 18 inches

r = 18/2 = 9 inches

Ball:

Circumference of ball = 30 inches

2πr = 30 inches

$2*3.14*r = 30\\\\r = \frac{30}{2*3.14}\\\\r = 4.8 inches$

Distance between the ball and the rim in a shot when the ball goes exactly in the center of the rim = radius of the rim - radius of the ball

   = 9 - 4.8

   = 4.2 inches