For this case, the first thing we must take into account is the following definition:
d = v * t
Where,
d: distance
v: speed
t: time
Substituting values we have:
Trip 1:
50 = v * t1
We cleared t1:
t2 = (50) * (1 / v)
Trip 2:
300 = (3 * v) * t2
We cleared t2:
t2 = (300/3) * (1 / v)
t2 = (100) * (1 / v)
Rewriting:
t2 = 2 (50) * (1 / v)
t2 = 2 * t1
Answer:
His new time compared with the old time was:
Twice the old time.
t2 = 2 * t1.
Answer:
19
Step-by-step explanation:
X will refer to the number.
X+57( the number added to the original.)=4x. (x time 4)
X+57=4x.
Subtract x from both sides to get the variable on one side.
(X+57)-x =(4x)-x
57=3x. You would then divide by 3 on both sides to again get integer isolated.
57/3=3/3x.
57/3=19. 3/3=1.
19=x.
X = 3 and x = 4 will make the polynomial = 0
answer
C. 3 and 4
