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Ivenika [448]
3 years ago
7

How many square inches are in 8 square feet? brainliest if u are right.

Mathematics
1 answer:
Katen [24]3 years ago
7 0
Theres 12 inches in a foot. So 12x8=96
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A company loses $5,400 as the result of a manufacturing defect. The 8 owners of the company must share the loss equally. What is
Ivahew [28]
Change in profit = x - (5,400/8)
3 0
3 years ago
Is the given number a solution of the equation?<br> 8=2+3; 10
kykrilka [37]

Answer:

No.

Step-by-step explanation:

8 doesn't equal 0 on the very right, which means it's not a solution to the equation.  So therefore, it is false based on the equation.

7 0
3 years ago
13 = m/4 + 7 can you show work too
lukranit [14]

The correct value of this equation is <u>m = </u><u>24</u>

<h3>Resolution method</h3>

This equation contains a fractional term. We note that the denominator of this equation is the <u>term 4</u>. Therefore, we will multiply the sides by <u>4</u>:

13 = m/4 + 7

13 . 4 = 4(m/4) + 7 . 4

52 = m + 28

Now, let's isolate the variable "as negative" and after the equality - we'll be subtracting the terms:

52 = m + 28

-m = 28 - 58

-m = -24

<u>m = 24</u>

Therefore, the correct value of this equation will be <u>m = 24</u>

7 0
2 years ago
7. Sarah draws a card from a standard deck, throws the card away, and then draws another card.
VashaNatasha [74]

Answer:

dependent

Step-by-step explanation:

7 0
3 years ago
What's the circumference of a circle that is 9cm? Please explain step by step of how you got the answer...
Sauron [17]

Formula for finding circumference of a circle is 2πr.

Step-by-step explanation:

  • The given question says what is the circumference of a circle that is 9cm.
  • As radius is required for finding circumference of a circle, the formula is 2πr.
  • Therefore taking the formula and substituting radius (r)= 9 cm. We get 2πr as 2×π×9 = 18π cm OR
  • If we substitute the value of π as 3.14 we will get⇒ 2×3.14×9= 56.52 cm.
  • So the circumference of the given circle would be 18π or 56.52 cms.
4 0
4 years ago
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