Answer:

Step-by-step explanation:
Given
--- interval
Required
The probability density of the volume of the cube
The volume of a cube is:

For a uniform distribution, we have:

and

implies that:

So, we have:

Solve


Recall that:

Make x the subject

So, the cumulative density is:

becomes

The CDF is:

Integrate
![F(x) = [v]\limits^{v^\frac{1}{3}}_9](https://tex.z-dn.net/?f=F%28x%29%20%3D%20%5Bv%5D%5Climits%5E%7Bv%5E%5Cfrac%7B1%7D%7B3%7D%7D_9)
Expand

The density function of the volume F(v) is:

Differentiate F(x) to give:




So:

Answer:
x=2/5
Step-by-step explanation:
Answer:
8.91
Step-by-step explanation:
Given: 0.95 = log x,
we can conclude that:
0.95 log x
10 = 10
0.95
which in turn is equivalent to x = 10 whose value is 8.91
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one day when I visit to dentist
Dentist: "You need a crown." -
Patient: "Finally someone who understands me"
It would weight 18lbs i believe