Answer:
For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 0.02 g/mi
Standard Deviation, σ = 0.01 g/mi
Sample size, n = 81
We are given that the distribution of level of nitrogen oxides is a bell shaped distribution that is a normal distribution.
Standard error due to sampling:

Formula:
We have to find the value of x such that the probability is 0.01
P(X > x)
Calculation the value from standard normal z table, we have,
For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.
Answer:
11
Step-by-step explanation:
2r - 7 = 15
2r = 15 + 7
2r = 22
r = 22 / 2
r = 11
no restricted values of x

<h3>All real numbers</h3>
Answer: 1/4 full.
Step-by-step explanation:
The question is asking for how much gas will be left in the tank after 2/3 of the gas in the tank is used.
There is currently 3/4 of the tank remaining.
To find 2/3 of 3/4, you can multiply the fractions together.
Do this by multiplying both numerators and both denominators:

Then, subtract 6/12 from 3/4. You can do this by simplifying the first fraction to 2/4 (divide both the numerator and denominator by 3).
3/4 - 2/4 = 1/4
There will be 1/4 of the tank left.
Answer:
B(1.4,0.4)
write x axis then y axis
it have 5line between 1 and 2
so 1/5=0.2
one line mean0.2