All categories

3 years ago

Polygon ABCD had the following vertices: A(-3,3), B(5,5), C(5,-4), and D(-3,-4) ASAP PlEaSE

Mathematics

1 answer:

Effectus [21]3 years ago

4 0

What’s the question asking? Is it needing side lengths or?

You might be interested in

Change 121/11 to a whole or mixed number

Mila [183]

Just divide 121 by 11 to get your answer.

8 0

3 years ago

Read 2 more answers

F(x)=3x²+4x-1 evaluate f(-2)

gtnhenbr [62]

Answer:

Step-by-step explanation:

f(-2) = 3(-2)^2 + 4(-2) - 1

= 12 - 8 - 1

= 3.

6 0

3 years ago

Please help me with this question and can u please do it on paper and take a pic of it. Thank You!

Likurg_2 [28]

click on pics click on pics

GodBless c:

4 0

3 years ago

Jan 18 Spiral Review Find the surface area of the following complex shapes.

zepelin [54]

Answer:

320 in.²

Step-by-step explanation:

Let's think of the shape as a normal rectangle with a height of 16 inches. Now all we need is the length. If you look at the right corner, it looks like a piece has been cut out. Since that piece has the same length and height of 8 inches, it is a square. This tells us the missing length of the entire length of the rectangle. Now the length of the rectangle is 16 inches + 8 inches, which is 24 inches.

The total area of the rectangle is 16 × 24, which is 384.

Then from the total area, we just need to subtract the area of the cut-out part. The area of the cut-out square is 8 × 8, which is 64.

384 - 64 = 320

The total surface area of the following complex shape is 320 in.²

4 0

2 years ago

Julian walked 6/10 of a mile to his friends house and another 35/100 mile to the store. He walked 1/4 of a mile back home. Julia

AveGali [126]

The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked $1\frac{1}{5} \text{ or } \frac{6}{5}$ miles.

Solution:

Given that,

Julian walked 6/10 of a mile to his friends house
Another 35/100 mile to the store
He walked 1/4 of a mile back home

To find total distance walked by Julian we have to add the above stated values. That is, $\frac{6}{10} +\frac{35}{100} +\frac{1}{4}$

Factors of 10 = $5\times2$

Factors of 100 = $5\times2\times5\times2$

Factors of 4 = $2\times2$

Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,

$\frac{6\times10}{10\times10} +\frac{35\times1}{100\times1} +\frac{1\times25}{4\times1}\rightarrow\frac{60+35+25}{100}\rightarrow\frac{120}{100}$

$\Rightarrow\frac{120}{100}\rightarrow\frac{6}{5}$

Which can also be written as $1\frac{1}{5}$ .

So, from the above calculation it can be said that Julian walked $1\frac{1}{5} \text{ miles }$ .

3 0

3 years ago